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raketka [301]
3 years ago
14

Alejandro bought 32 kiwi fruits for $16. how many kiwi can he buy if he only had with $4.50

Mathematics
2 answers:
Kaylis [27]3 years ago
7 0
Answer: 9

Explanation:
slavikrds [6]3 years ago
3 0
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Florian ran 1.2 miles and walked 4.8 laps around the path at the park for a total distance of 3.6 miles. Which shows the correct
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Answer:

The correct answer would be D) 4.8x + 1.2 = 3.6; x = 0.5 mile

Step-by-step explanation:

This is because laps would be the dependent variable, so we know the number of them (4.8) would be multiplied by the variable (x). We also know that 1.2 is the constant. Now we can solve to make sure this is the right equation.

4.8x + 1.2 = 3.6

4.8x = 2.4

x = 0.5

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Hey buddy I got your answer
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Semmy [17]

Answer:7

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3 years ago
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Please solve and show work
pychu [463]

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12

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7 0
3 years ago
Functionally important traits in animals tend to vary little from one individual to the next within populations, possibly becaus
const2013 [10]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X:  Ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloth.

The researcher's claim is that the ratio of the SC of the sloths is more variable than in other animal species that are more active.

For more active species the standard deviation of the ratio is σ= 0.09

1)

To calculate the sample standard deviation you have to calculate the sample variance first:

S^2= \frac{1}{n-1} [sumX^2-\frac{(sumX)^2}{n} ]

n=7; ∑X= 8.91; ∑X²= 11.8599

S^2= \frac{1}{6} [11.5899-\frac{(8.91)^2}{7} ]= 0.0287= 0.029

S= √S²= √0.029= 0.169≅ 0.17

The sample standard deviation of the ratio is 0.17

2)

The parameter of interest is the population standard deviation. To calculate a confidence interval for the standard deviation of a population you have to estimate the population variance first. Then calculate the square root of both limits of the interval for the variance to obtain the interval for the standard deviation.

The statistic to use is the Chi-Square and the formula for the interval is:

[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]

X^2_{n-1;\alpha /2}= X^2_{6; 0.025}= 1.2373

X^2_{n-1;1-\alpha /2}= X^2_{6; 0.975}= 14.449

[\frac{6*0.029}{14.449} ;\frac{6*0.029}{1.2373} ]\\

[0.0120; 0.1406]

Using a 95% confidence level you'd expect the interval [0.0120; 0.1406] to include the true value of the population variance of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

Now you have to calculate the square root of each limit:

[√0.0120; √0.1406]

[0.1097; 0.3750]

Using a 95% confidence level you'd expect the interval [0.1097; 0.3750] to include the true value of the population standard deviation of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

3)

As you can see the calculated interval doesn't include the value obtained for the other species.

I hope this helps!

5 0
3 years ago
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