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3 years ago

An object is at rest on a table. The gravitational force is 10 N down, and the normal force is 10 N up. What is the net force?

Mathematics

2 answers:

weqwewe [10]3 years ago

8 0

N + G = F(net)

N=+10 N, G=-10 N;

So, +10+(-10)=0

Answer is F(net) = 0 N.

Anastasy [175]3 years ago

5 0

---> 0 <---

suppose this "0" is an arbitary object. The net force will be against it from both sides (left and right)

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Mademuasel [1]

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3 years ago

Samuel is six inches taller than his brother Elijah.if Samuel is 48 inches tall,how tall is Elijah

GarryVolchara [31]

Answer:

If Samuel is 6 inches taller than Elijah and he is 48 inches tall then Elijah is 42 inches tall.

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3 years ago

Read 2 more answers

PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM

Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

$c^{2} =a^{2} +b^{2}$

c = $\sqrt{a^{2} +b^{2} }$

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = $\sqrt{40^{2} + 9^{2} }$

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = $\sqrt{12^{2} + 13^{2} }$

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$35^{2} = 20^{2} + b^{2}$

1225 = 400 + $b^{2}$

$b^{2}$ = 1225 - 400

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$\sqrt{b^{2} } = \sqrt{825}$

b = 5 $\sqrt{33}$

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$37^{2} = 20^{2} + b^{2}$

1369 = 400 + $b^{2}$

$b^{2}$ = 1369 - 400

$b^{2}$ = 969

Taking square root on both sides

b = 31.12

Hope it helps.

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2 years ago