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anygoal [31]
3 years ago
11

Please help. The question is in the picture

Mathematics
1 answer:
Roman55 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

sorry cant help not in high school yet so yikes that is gibberish to me

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Sunshine High School claims that 72% of its students complete their homework on a daily basis. Ms. Carter surveyed 80 students a
Ulleksa [173]

Answer: z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

Step-by-step explanation:

let p be the population proportion of students complete their homework on a daily basis.

As per given , we have

p= 0.72

sample size : n= 80

Sample proportion : \hat{p}=0.60

Test statistic for proportion:

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

i.e.

z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(1-0.72)}{80}}}

i.e.

z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(0.28)}{80}}}

That is , z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

6 0
3 years ago
Helpppppppppppppppppppppppppp
Yuri [45]

Answer:

3 : 7

7 : 3

Step-by-step explanation:

you have 3 shovels for every 7 buckets

the ratio of buckets to shouvels is 7 to 3

6 0
3 years ago
Read 2 more answers
Select the correct answer.
aleksklad [387]

Answer:

R(2, 4)

Step-by-step explanation:

The general equation for a circle centered at (h,k) with radius, R, is  

(x-h)^2 + (y-k)^2 = R^2

Putting the values in formula,

(x-6)^2 + (y-1)^2 = 5^2

Putting the coordinates (2, 4) of the answer B(2-6)^2 + (4-1)^2 = 25

(-4)^2 + 3^2 = 25

16 + 9 = 25

25 = 25

R.H.S = L.H.S

So according to the above solution,

B) R(2, 4), is the correct answer.

5 0
3 years ago
1/2+1/4= <br><br> 3/4+1/4=<br><br> What is the difference
son4ous [18]
1/2 + 1/4 = 3/4
3/4 + 1/4 = 1
4 0
3 years ago
Read 2 more answers
Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4
Alik [6]

Answer:

\alpha=3

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

(x-h)^2+(y-k)^2=r^2

We are given the equation of a circle as

3x^2+3y^2-6\alpha x+12y-3\alpha=0

Note we have corrected it by adding the square to the y. Simplify by 3

x^2+y^2-2\alpha x+4y-\alpha=0

Complete squares and rearrange:

x^2-2\alpha x+y^2+4y=\alpha

x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4

(x-\alpha)^2+(y+2)^2=r^2

We can see that, if r=4, then

\alpha+\alpha^2+4=16

Or, equivalently

\alpha^2+\alpha-12=0

There are two solutions for \alpha:

\alpha=-4,\ \alpha=3

Keeping the positive solution, as required:

\boxed{\alpha=3}

8 0
3 years ago
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