Answer:
D
Step-by-step explanation:
The difference between 63y and 35y is 28y. 28/2=14, 28/4=7, 28/7=4, 28/9=not whole number so I'm not doing the math, and to make sure we are right, 28/14=2
There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Answer:
192x^4 - 192 x^3i
Step-by-step explanation:
a^3 b
Lets find a^3
a=4x
a^3
(4x)^3
64x^3
b = 3x-3i
a^3b
(64x^3) * (3x-3i)
Distribute
64x^3*3x - 64x^3 *3i
192x^4 - 192 x^3i
Answer:
2 and 14?
Step-by-step explanation:
Multiplied together they are 28, but I don't know if that's what you were asking
Answer:
20
Step-by-step explanation:
g(3)= 3²+4·3-1
9+4·3-1
9+12-1
21-1=20