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torisob [31]
3 years ago
7

Tickets to the school play are $5.00 for adults and $3.50 for students. If the total value of all the tickets sold was $2517.50

and 100 more student bought tickets than adults, how many adults amd students bought tickets
Mathematics
1 answer:
Irina-Kira [14]3 years ago
6 0
x-\ adults\\
y-\ students\\\\  \left \{ {{5x+3.50y=2517.5} \atop {x+100=y}} \right.\\\\
5x+3.5(x+100)=2517.5\\\\
5x+3.5x+350=2517.5\ \ \ | subtract\ 350\\\\
8.5x= 2167,5\ \ \ | divide\ by\ 8.5\\\\
x=255\\\\
y=355\\\\
There\ were\ 355\ student\ tickets\ and\ 255\ adult\ tickets.
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Read 2 more answers
20 points
SVEN [57.7K]

Answer:

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Step-by-step explanation:

Given data

Length= 24 in

Width = 18 in

Diagonally, we need to find using the Pythagoras theorem

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3 years ago
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NNADVOKAT [17]

Answer: <em> 9\ rows</em>

Step-by-step explanation:

<h3> <em>The complete exercise is:"A gardener has 27 tulip bulbs, 45 tomato plants, 108 rose bushes, and 126 herb seedlings to plant in the city garden. He wants each row of the garden to have the same number of each kind of plant. What is the greatest number of rows that the gardener can make if he uses all the plants?"</em></h3><h3 />

The first step to solve the exercise is to find the Greatest Common Factor (GCF) between 27, 45, 108 and 126.

You can follow these steps in order to find the GCF:

1. You must decompose 27, 45, 108 and 126into their prime factors:

27=3*3*3=3^3\\\\45=3*3*5=3^2*5\\\\108=2*2*3*3*3=2^2*3^3\\\\126=2*3*3*7=2*3^2*7

2. You must multiply the commons with the lowest exponents. Then:

<em>GCF=3^2\\\\GCF=9</em>

Therefore, the greatest number of rows that the gardener can make if he uses all the plants is:

9\ rows

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3 years ago
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