Answer:
We have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO.
Step-by-step explanation:
Let us assume that ABCD is a parallelogram having diagonals AC and BD.
We have to prove that in a parallelogram the diagonals bisect each other.
Assume that the diagonals of ABCD i.e. AC and BD intersect at point O.
Therefore, to prove that the diagonals AC and BD bisect each other, we have to first prove that Δ ABO and Δ CDO are congruent or Δ DAO and Δ BCO are congruent.
In symbol, we have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO. (Answer)
The answer is B.) 1/4 because it goes 1 up and 4 right.
Answer:
22
Step-by-step explanation:
The problem can be solved geometrically. By this way, the solution is going to be easy, as well.
We can see from the attached graph that the coordinates are the vertexes.
Considering a unit distance, we can find that the width of this rectangle is:
4 = 12 - 8
and the length is:
7 = 6-(-1)
Then, the perimeter is P = (4+7)*2 = 22
y is part of a right angle on line AB
a right angle = 90 degrees
90-47 = 43 degrees
y = 43 degrees
a straight line = 180 degrees
180-47 = 133 degrees
x = 133 degrees