To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4
x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)
Answer:
295X12
Step-by-step explanation:
GOOD LUCK
X^2 - 25 is a difference of squares which has a special factorization.
In general, a^2 - b^2 = (a + b)(a - b)
x^2 - 25 = 0
(x + 5)(x - 5) = 0
x + 5 = 0 or x - 5 = 0
x = -5 or x = 5
Can you like show a picture because I don’t understand what you tryna ask
Answer:
x=1
Step-by-step explanation:
x = -4 + 6 + (11 + 4(-3)).
First get the numbers in the parentheses
x = -4 + 6 + (11 - 12)
Since 11 - 12 = -1. We can replace (11-12) with -1
x = -4 + 6 -1
Now add and subtract
x = 1
