Answer:
24.72 m
11.53 m
Step-by-step explanation:
Horizontal distance AB can be obtained from △ABC
From trigonometry :
Sin18° = opposite / hypotenus
Sin18° = AB / 80
AB = 0.3090169 * 80
AB = 24.72 m
The height BT, of tower from △ABT
From trigonometry :
Tan25° = opposite / Adjacent
Tan25° = h / 24.72m
h = Tan25 * 24.72
h = 11.527
h = 11.53 m
Hence, height of tower BT = 11.53 m
For this it would simply be part over whole to figure out the percentage we would do (239/817)*100. This comes out to around 29.25% of the students are remote
Answer:
∠J= 22°
JL=19.0137
KL=7.99
Step-by-step explanation:
The step-by-step is attached as a picture. Hope it helps! Feel free to message me if you have any questions in reference to this math problem.
The answer to the problem you sent me in the comments is attached to here too.
Answer:
Mr. Sato needs 9 more magnets.
Step-by-step explanation:
The 24 students will form 12 pairs. The total number of magnets needed is 12*3 = 36. Mr. Sato gave out 9*3=27 magnets already and so he will need 36 - 27 = 9 more magnets.
So distributive=ab+ac=a(b+c)
so
find the gcf of 4 and 12
4=2 time 2
12=2 times 2 times \3
the gcf is 2 times 2 =4
4(d+3e)
