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Zina [86]
3 years ago
13

The chart shows the low temperature each day in International Falls, Minnesota, during the month of February 2009. What was the

median low temperature in International Falls for the first week of the month?

Mathematics
2 answers:
Nastasia [14]3 years ago
6 0

Answer:

The median is -8°F

Step-by-step explanation:

Attached Table.

The median is the "middle" value from all the numbers arranged from least to greatest.

Looking at the table, we need to arrange the numbers (first week numbers) from least to greatest.

-31, -29, -9, -8, 3, 4, 6

There are 7 numbers and the middle number is the 4th one, which is -8

The median is -8°F

Lelu [443]3 years ago
4 0

Answer:

-8 F

Step-by-step explanation:

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For each of the sequence below identify whether there is a common ratio. If there is identity what it is. If there is not a comm
vfiekz [6]

yes

1.-3

2.3

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6 0
3 years ago
Determine whether ∆DEF=∆JKL, given that D(2,0), E(5,0), F(5,5), J(3,-7), K(6,-7), and L(6,-2)
raketka [301]

Answer:

Yes , triangle DEF is congruent to JKL

Step-by-step explanation:

Given:

The coordinates of triangle DEF are;

D (2, 0)

E(5. 0)

F(5, 5)

and

the coordinates of triangle JKL are:

J(3, -7)

K(6, -7)

L (6, -2)

The rule of translation is used on triangle DEF to get triangle JKL:

(x , y) \rightarrow (x+1 , y-7)

i.e

D (2, 0) \rightarrow (2+1 , 0-7) = (3, -7) =  J

E (5, 0) \rightarrow (5+1 , 0-7) = (6, -7) =  K

F (5, 5) \rightarrow (5+1 , 5-7) = (6, -2) = L

As, we know that two triangles are known as congruent if there is an isometry mapping one of the triangles to the other.

therefore, triangle DEF congruent  to triangle JKL



8 0
3 years ago
Determine the degree for the following functions 4x 5 + 3x 2 + 24 23x 3 – 35x 15 + 45x 9
Aneli [31]

Answer:

  1. 5
  2. 15

Step-by-step explanation:

We assume your expressions are ...

  4x^5 + 3x^2 + 24

  23x^3 – 35x^15 + 45x^9

The exponents of the variable in the terms of the first expression are ...

  5, 2, 0

The largest of these values is 5, so the first expression has degree 5.

__

The exponents of the variable in the terms of the second expression are ...

  3, 15, 9

The largest of these values is 15, so the second expression has degree 15.

4 0
3 years ago
In a circle with radius 4 cm the diameters AC and BD are perpendicular to each other. Prove that ABCD is a square. Find the area
Usimov [2.4K]
This can be proven by using the Pythagorean theorem.    Draw a circle and label the radius 4 cm.  Then draw the diameters in to create a perpendicular intersection at the center.  If you then label the points that make the diameter, you will see that when connected they create right isosceles triangles.  a^2 + b^2 = c ^2, so 4 x 4 + 4 x 4 = c^2.  32 = c^2.  Because you are going to be multiplying it by itself to calculate the area, you have you answer of 32 square centimeters.  NO need to find the square root and them square it again!
8 0
3 years ago
Find the fraction half way between 1/7 and 1/5
Masja [62]

Answer:

6/35

Step-by-step explanation:

add ¹/7+¹/5 =12/35

divide 12/35 by 2

=6/35

4 0
3 years ago
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