Determine whether ∆DEF=∆JKL, given that D(2,0), E(5,0), F(5,5), J(3,-7), K(6,-7), and L(6,-2)
raketka [301]
Answer:
Yes , triangle DEF is congruent to JKL
Step-by-step explanation:
Given:
The coordinates of triangle DEF are;
D (2, 0)
E(5. 0)
F(5, 5)
and
the coordinates of triangle JKL are:
J(3, -7)
K(6, -7)
L (6, -2)
The rule of translation is used on triangle DEF to get triangle JKL:

i.e
= J
= K
= L
As, we know that two triangles are known as congruent if there is an isometry mapping one of the triangles to the other.
therefore, triangle DEF congruent to triangle JKL
Answer:
- 5
- 15
Step-by-step explanation:
We assume your expressions are ...
4x^5 + 3x^2 + 24
23x^3 – 35x^15 + 45x^9
The exponents of the variable in the terms of the first expression are ...
5, 2, 0
The largest of these values is 5, so the first expression has degree 5.
__
The exponents of the variable in the terms of the second expression are ...
3, 15, 9
The largest of these values is 15, so the second expression has degree 15.
This can be proven by using the Pythagorean theorem. Draw a circle and label the radius 4 cm. Then draw the diameters in to create a perpendicular intersection at the center. If you then label the points that make the diameter, you will see that when connected they create right isosceles triangles. a^2 + b^2 = c ^2, so 4 x 4 + 4 x 4 = c^2. 32 = c^2. Because you are going to be multiplying it by itself to calculate the area, you have you answer of 32 square centimeters. NO need to find the square root and them square it again!
Answer:
6/35
Step-by-step explanation:
add ¹/7+¹/5 =12/35
divide 12/35 by 2
=6/35