Which investment is better 6.15% compounded monthly or 6.21% compounded quarterly

Add. Write your answer in simplest form.

alexandr1967 [171]

Answer:

yes, you got it correct

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Plz help question is in pic 20 points!!

emmasim [6.3K]

Answer:

AB/2 = 6 and 12 = AB

Step-by-step explanation:

5 0

2 years ago

Abnormalities In the 1980s, it was generally believed that congenital abnormalities affected about 5% of the nation’s chil-dren.

Ainat [17]

Answer:

Null hypothesis: $p\leq 0.05$

Alternative hypothesis: $p>0.05$

The conditions and requirements are explained on detail below.

Step-by-step explanation:

1) Data given and notation n

n=384 represent the random sample taken

X=46 represent the children with abnormalities in the sample

$\hat p=\frac{46}{384}=0.120$ estimated proportion of children with abnormalities in the sample

$p_o=0.05$ is the value that we want to test

$\alpha$ represent the significance level (no given)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= proportion of children with congenital abnormalities

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of children with congenital abnormalities exceeds 5%. :

Null hypothesis: $p\leq 0.05$

Alternative hypothesis: $p>0.05$

We assume that the proportion follows a normal distribution.

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ .

<em>Check for the assumptions that he sample must satisfy in order to apply the test</em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =384*0.05=19.2>10$

$n(1-p_o)=384*(1-0.05)=364.8>10$

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.120 -0.05}{\sqrt{\frac{0.05(1-0.05)}{384}}}=6.29$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided usually is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =P(z>6.29)=1.59x10^{-10}$

Based on the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of children with abnormalities exceeds 0.05 or 5% .

4 0

4 years ago

What two numbers multiply to get 3 and add to get 6

julia-pushkina [17]

Answer:

3

Step-by-step explanation:

4 0

3 years ago

Given the original statement "If a number is negative, the additive inverse is positive,” which are true? Select three options.

Sergeu [11.5K]

Answer:

The three options are;

1) If p = a number is negative and q = the additive inverse is positive, the original statement is p → q

2) If p = a number is negative and q = the additive inverse is positive, the original statement the inverse of the original statement is ~p → ~q

3) If q = a number is negative and p = the additive inverse is positive, the contrapositive of the original statement is ~p → ~q

Step-by-step explanation:

Given a statement if p then q, we have, p → q. The converse of the original statement is then, if q, then p while the inverse of the original statement is then if not p then not q, and the contrapositive statement is then if not q then not p

Mathematically, we have;

The given conditional statement;

If a number is negative, the additive inverse is positive which can be expressed as follows;

The conditional statement is p → q

The converse statement is q → p

The inverse statement is ~p → ~q

The contrapositive statement is ~q → ~p

Therefore, we have;

1) The conditional statement, if p = a number is negative and q = the additive inverse is positive, the original statement which is a conditional statement is therefore p → q

2) If p = a number is negative and q = the additive inverse is positive, the original statement, which is a conditional statement is p → q, the inverse of the original conditional statement is therefore, ~p → ~q

3) If q = a number is negative and p = the additive inverse is positive, the original statement, which is a conditional statement is therefore, q → p, the contrapositive of the original conditional statement is therefore ~p → ~q.

3 0

3 years ago