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Komok [63]
4 years ago
15

Is a empty set a subset of every set

Mathematics
1 answer:
Thepotemich [5.8K]4 years ago
8 0

Answer:

Subsets That Make Up the Real Numbers. The set of real numbers is made up of the rational and the irrational numbers. Rational numbers are integers and numbers that can be expressed as a fraction.


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Dana has a triangular piece of fabric. The height of the triangle is 25 inches and the triangle's base is 4 inches. Mona says th
Neko [114]

Answer:

50

Step-by-step explanation:

the formula to find the area of a triangle is

half base times height or

½base×height

6 0
3 years ago
98 Points And Brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!A poll asked 15 men in two age groups, 30 and younger and older than 3
bekas [8.4K]
The first thing you need to do is classify all the men into 4 groups which are:
1) 30 and younger with facial hair: 4
2) older than 3 with facial hair: 5
3) 30 and younger with facial hair: 3
4) older than 30 without facial hair: 4


Question (a): Make a two-way table of the data. Of the men surveyed, how many were 30 and younger? How many did not have facial hair.

                                   with facial hair          without facial hair          total
30 & younger                         4                                     3                          7
older than 30                         5                                     3                          8
total                                        9                                    6                          15
From the data you can see that:
7 men were 30 and younger and 6 men did not have facial hair.


Question (b): Create a two-way relative frequency table that displays the relative frequency of the men 30 and younger and of the men older than 30 who had or did not have facial hair. Express your answer as decimals written to three decimal places.

                               with facial hair          without facial hair          total
30 and younger             4/15                           3/15 = 1/5                 7/15
older than 30             5/15 = 1/3                      3/15 = 1/5                 8/15
total                            9/15 = 3/5                      6/15 = 2/5                   1


Question c: What percent of men older than 30 had facial hair?
The percent is equal to the relative frequency times 100% so in this case it is equal to (1/3) * 100% = 33.33%

Hope this helps!!!   :)
3 0
3 years ago
6 boys and 6 girls attend a birthday party and play pin the tail on the donkey. how many different arrangements of first, second
Natali5045456 [20]
Given that there are <span>6 boys and 6 girls in a birthday party, the number of different arrangements of</span><span> first, second, and third is given by:

^{12}P_3= \frac{12!}{(12-3)!}  \\  \\ = \frac{12!}{9!} = \frac{12\times11\times10\times9!}{9!}  \\  \\ =12\times11\times10=1,320</span>
7 0
3 years ago
The ratio of the perimeters of two similar triangles is 4:7. The sides of the larger triangles are 10, 12, and 13cm,
rjkz [21]

Answer:

Perimeter = 20cm

The perimeter is 35 for the larger triangle = 7:4 ratio

the perimeter for the smaller triangle = 4:7 ratio

We add up 4+7 = 11 and multiply 35 x 2 = 70.

so that the smaller triangle = 40  = 40:70

35 = 7 and 20 = 4

To find measurements of 20

we have any number over 10 combined will make the smaller sides possible,

Where hypotenuse would be under 10.

H = 6.5 Sides = 6 + 5 does not add up to 20

H = 9 Sides = 7 + 4  does have near equal spaced symmetry.

H = 9  Sides = 5 + 6  is wrong as no symmetry in measure

H = 8  Sides = 7 + 5 is wrong as no symmetry in measure

H = 7 Sides = 6 + 7  is wrong as equal sides

H = 6 sides = 6.5 + 6.5 is wrong as equal sides

H = 11 Sides = 6 + 3 is wrong has no symmetry.

The measurements must be 9cm, 7cm and 4 cm for the smaller triangle

The perimeter adds up to 20cm.    

7 0
4 years ago
WILL MARK BRAINLIEST!!!
Vadim26 [7]

Answer:

one on the left is p=139. one on the right is p=117 I believe this is the right answers if not then I'm sorry

8 0
3 years ago
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