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3 years ago

Jane is going to fence in her back yard. She has purchased 150 feet of

Mathematics

1 answer:

Alborosie3 years ago

7 0

D. x+ 40 = 150 this is the answer

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Graph and write the solution: Y= x - 4 Y= 1/3x - 2

Reika [66]

Answer:

1. x=4

2. x=6

Step-by-step explanation:

I've attached the graphs here:

Clearly, the solution for first one is(Reminder: the solution is the x-intercepts, when y is zero):

x=4

And the second is:

x=6

Hope this helps!

Mark brainliest if you think I helped! Would really appreciate!

6 0

3 years ago

What are all the factors of 618?

Reika [66]

Answer:

1, 2, 3, 6, 103, 206, 309, 618

3 0

2 years ago

Find the curl of ~V ~V = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

7 0

3 years ago

How do you find the lease common fatcor

8_murik_8 [283]

Answer:

One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

Step-by-step explanation:

4 0

3 years ago

Plss help me and explaim too

masya89 [10]

Answer:

a = b = 1

Step-by-step explanation:

The triangles are similar thus ratios of corresponding sides are equal, that is

$\frac{10}{2}$ = $\frac{5}{b}$ ( cross- multiply )

10b = 10 ( divide both sides by 10 )

b = 1

and

$\frac{10}{2}$ = $\frac{5}{a}$ ( cross- multiply )

10a = 10 ( divide both sides by 10 )

a = 1

Thus a = 1 and b = 1

3 0

3 years ago