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4 years ago

19.86 + 7.091 plz I have a test tomorrow

Mathematics

2 answers:

xenn [34]4 years ago

7 0

26.951 is the answer

vlada-n [284]4 years ago

3 0

26.851 u can also type that on calculator

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

yarga [219]

Answer:

$(x-5)^2+(y-2)^2=9\\$

Step-by-step explanation:

So, you basically want the equation of the circle.

Given:

Center(C): $C(5, 2)$

$r=3$

The equation of circle is:

$(x-h)^2+(y-k)^2=r^2\\$

Where, $(h, k)$ represents the center point and $r$ is the radius of the circle.

Plotting the values in the equation:

$(x-5)^2+(y-2)^2=3^2\\$

$(x-5)^2+(y-2)^2=9\\$

This is the equation of the circle of center (5, 2) and radius 3.

6 0

3 years ago

Find the perimeter of the following triangle.

pashok25 [27]

Hello!

To find the perimeter of the triangle, we need to find the length of all the sides using the distance formula.

The distance formula is: $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

First, we can find the distance between the points (-3, -1) and (2, -1). The point (-3, -1) can be assigned to $(x_{1},y_{1})$ , and (2, -1) is assigned to $(x_{2},y_{2})$ . Then, substitute the values into the formula.

$d =\sqrt{(2 - (-3))^{2}+ (-1 - (-1))^{2}}$

$d =\sqrt{5^{2}+0^{2}}$

$d =\sqrt{25} = 5$

The distance between the points (-3, -1) and (2, -1) is 5 units.

Secondly, we need to find the distance between the points (2, 3) and (2, -1). Assign those points to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then substitute it into the formula.

$d =\sqrt{(2 - 2)^{2}+ (-1 - 3)^{2}}$

$d =\sqrt{0^{2}+(-4)^{2}}$

$d =\sqrt{16} = 4$

The distance between the two points (2, 3) and (2, -1) is 4 units.

Finally, we use the distance formula again to find the distance between the points (-3, -1) and (2, 3). Remember the assign the ordered pairs to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ and substitute!

$d =\sqrt{(2 -(-3))^{2}+ (3 - (-1))^{2}}$