These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer:
11.1%
Step-by-step explanation:
17/153= 0.111 x 100= 11.1%
Answer:
The rate of interest for compounded annually is 6.96 % .
Step-by-step explanation:
Given as :
The principal amount = Rs 4600
The time period = 5 years
The amount after 5 years = Rs 6440
Let The rate of interest = R %
<u>From compounded method</u>
Amount = Principal × 
or, Rs 6440 = Rs 4600 × 
Or, 
=
or, 1.4 =
Or, 
= 1 + 
or, 1.0696 = 1 +
or, = 1.0696 - 1
Or, = 0.0696
∴ R = 0.0696 × 100
I.e R = 6.96
Hence The rate of interest for compounded annually is 6.96 % . Answer
Answer:
You can't have a single answer.
Step-by-step explanation:
An indiviual equation can't be solved if it has 2 variables.
You can, however, graph it.
The line will create all the possible sets of answers for the problem.
