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AnnyKZ [126]
2 years ago
6

Barun said says, "The number sqrt49 is an irrational number." Do you agree or disagree? Explain using the definition of rational

and irrational numbers.
Mathematics
1 answer:
Brums [2.3K]2 years ago
3 0
<h3>Answer: Disagree. sqrt(49) is rational</h3>

Here's why:

sqrt(49) = sqrt(7^2) = 7

We can write 7 as a ratio or fraction of two integers 7 = 7/1

This shows that 7 is rational, so that makes sqrt(49) rational as well.

An irrational number is one where we cannot write it as a fraction of two integers. An example of an irrational number would be pi. Another irrational number is sqrt(2).

Note: the denominator can never be zero.

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Answer:

15 and 6

Step-by-step explanation:

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3 years ago
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(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti
Rashid [163]

Answer:

The solution

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

<em>Step(i)</em>:-

Given differential problem

                           y′+3 y=9 t

<em>Take the Laplace transform of both sides of the differential equation</em>

                L( y′+3 y) = L(9 t)

 <em>Using Formula Transform of derivatives</em>

<em>                 L(y¹(t)) = s y⁻(s)-y(0)</em>

  <em>  By using Laplace transform formula</em>

<em>               </em>L(t) = \frac{1}{S^{2} }<em> </em>

<em>Step(ii):-</em>

Given

             L( y′(t)) + 3 L (y(t)) = 9 L( t)

            s y^{-} (s) - y(0) +  3y^{-}(s) = \frac{9}{s^{2} }

            s y^{-} (s) - 7 +  3y^{-}(s) = \frac{9}{s^{2} }

Taking common y⁻(s) and simplification, we get

             ( s +  3)y^{-}(s) = \frac{9}{s^{2} }+7

             y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

<em>Step(iii</em>):-

<em>By using partial fractions , we get</em>

\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}

  \frac{9}{s^{2} (s+3} =  \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}

 On simplification we get

  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

 Put s =0 in equation(i)

   9 = B(0+3)

 <em>  B = 9/3 = 3</em>

  Put s = -3 in equation(i)

  9 = C(-3)²

  <em>C = 1</em>

 Given Equation  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

  9 = A s²+3 A s +B(s)+3 B +C(s²)

 <em> 0 = A + C</em>

<em>put C=1 , becomes A = -1</em>

\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}

<u><em>Step(iv):-</em></u>

y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

y^{-}(s)  =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}

Applying inverse Laplace transform on both sides

L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})

<em>By using inverse Laplace transform</em>

<em></em>L^{-1} (\frac{1}{s} ) =1<em></em>

L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}

L^{-1} (\frac{1}{s+a} ) =e^{-at}

<u><em>Final answer</em></u>:-

<em>Now the solution , we get</em>

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}

           

           

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Evaluate the expression.<br><br> (132−122)÷5<br> The value of the expression___ is
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The answer is 107.6 pemdas order of operations
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2 years ago
Leon has already run 1 mile on his own, and he expects to run 3 miles during each track practice. Write an equation that shows t
maks197457 [2]

Answer:

d = 1 + 3p  

Step-by-step explanation:

Leon already ran 1 miles on his own and he is expected to cover a distance d of 3 miles during each practice. The number of practices is expressed as p and the distance covered is expressed as d.

For every track practice he is expected to cover a distance of 3 miles. Recall he has already cover 1 mile on his own.

Therefore, the relationship between the practices p and the distance d can be expressed as follows.

number of track practice = p

distance covered = d

The distance covered  d in miles is 1 miles plus the number of track practice p multiply by 3

d = 1 + 3p  

5 0
3 years ago
Isabella spent $49 for 7 bracelets. Each bracelet cost the same amount.
n200080 [17]
To answer this question, we first have to set up an equation with variables.
We can use "x" to represent the cost of each bracelet.

Equation: number of bracelets bought × cost of each bracelet = total cost

Number of bracelets bought: 7
Total Cost: 49

Using this information, we can fill in the equation and solve for x.

7x = 49

To isolate x, divide both sides by 7.

x = 7

Since x equals 7, we now know that each bracelet cost $7.
3 0
3 years ago
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