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katovenus [111]
3 years ago
10

Stella bought 14 purses for $50. The next day she bought 2 more for a total of $38. What was the mean cost per purse?

Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

$48.5

Step-by-step explanation:

Given data

Number of purses= 14+2= 16

Cost of 14 purses= $50

Cost of 2 purses= $38

Let us use the weighted cost method

Mean cost = (14*50+ 2*38)/16

Mean cost = (700+ 76)/16

Mean cost = 776/16

Mean cost =$48.5

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A photocopy machine can print 735 copies in 7 minutes.what is the rate at which the machine prints the copies per minute
11111nata11111 [884]

The copy machine makes 105 copies per minutes.

Step-by-step explanation:

Given,

Copies printed by photocopy machine = 735

Time taken by machine = 7 minutes

To find the unit rate in terms of minutes, we will divide the copies printed by machine by the time taken.

Copies printed in one minute = \frac{735}{7}

Copies printed in one minute = 105 copies

The copy machine makes 105 copies per minutes.

Keywords: unit rate, division

Learn more about unit rate at:

  • brainly.com/question/12980528
  • brainly.com/question/12981512

#LearnwithBrainly

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3 years ago
(2 - 3)4(4) - 9 ÷ 3.
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4 years ago
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3 years ago
Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).
Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).

Then

\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.

2. Find

\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).

Then

\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.

3. Find

\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).

Then

\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.

4.

\angle E=\arccos0=\dfrac{\pi}{2},\\ \\&#10;\angle D=\arccos\letf(\sqrt{\dfrac{37}{83}}\right)\approx 0.27\pi,\\ \\&#10;\angle F=\arccos\letf(\sqrt{\dfrac{46}{83}}\right)\approx 0.23\pi.

3 0
3 years ago
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