Given equation: y =2x^2+12x+13.
We need to find the axis of symmetry and the coordinates of the vertex of the graph of the function.
The formula of axis of symmetry is : .
a= 2 and b=12.
Therefore, .
Let us find y-coordinate of the vertex.
Plugging x=-3 in given quadratic y =2x^2+12x+13.
y= 2(-3)^2+12(-3)+13 = 2(9) -36 +13 = 18-36 +13 = -5.
We got x-coordinate of the vertex -3 and y-coordinate of the vertex -5.
<h3>Therefore, vertex of the graph is (-3,-5).</h3>Answer:
There are infinite number of triangles that could be achieved with those angles.
To picture this, we only have to imagine a triangle that is either smaller or bigger than the one at hand.
Tracing a series of paralell lines (which guarantee that the angles are being kept), we can draw triangles for infinite values of x,y and z.
