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Vladimir [108]
3 years ago
6

Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function:

Mathematics
1 answer:
sukhopar [10]3 years ago
7 0

Given equation: y =2x^2+12x+13.

We need to find the axis of symmetry and the coordinates of the vertex of the graph of the function.

The formula of axis of symmetry is : -\frac{b}{2a}.

a= 2 and b=12.

Therefore, -\frac{b}{2a} = -\frac{12}{2(2)}  = -\frac{12}{4} = -3.

<h3>Therefore, axis of symmetry is x=-3.</h3>

Let us find y-coordinate of the vertex.

Plugging x=-3 in given quadratic y =2x^2+12x+13.

y= 2(-3)^2+12(-3)+13 = 2(9) -36 +13 = 18-36 +13 = -5.

We got x-coordinate of the vertex -3 and y-coordinate of the vertex -5.

<h3>Therefore, vertex of the graph is (-3,-5).</h3>
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∠ URS is an external angle to Δ QUR, that is

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