Answer:
Both of these examples are wrong. You cannot add/subtract integers and square roots together, however, you could add square roots together if they have the same number under the square root. For example, 2 - 2√6 will stay as 2 - 2√6 because they aren't like terms. 25 + 5√5 + 5√5 + 5 = 30 + 10√5 because 25 + 5 = 30 and 5√5 + 5√5 = 10√5. We can add 5√5 and 5√5 together because they have the same number under the square root. If we were to compute √2 + √3, we would just leave it as is because they don't have the same number under the square root.
You already know that y equals -4. It says that x equals 3, so multiply the -4 by 3 and because it has a negative number and a positive number it will equal -12. Remember anytime you see a letter after a number it means multiply. The complete problem should be -10 because 2 is a whole number you subtract it from -12. Hope that helped you out some.
Answer:Jeff read 11 books<em> I believe </em>
Step-by-step explanation:hope this helps
Answer:
31:150
Step-by-step explanation:
First of all we convert the hours into minutes:
5×60=300
which gets us 42:300, which we can simplify to:
31:150
and is 31 is prime and 150 can't be divided into it without a remainder, it is in it's simplest form and it is the answer.
It takes value from a user and then user the operation of (+,-,*/).
i used c++ programming language to solve this program:
#include<iostream>
using namespace std;
int main() {
int var1, var2;
char operation;
cout << "Enter the first number : ";
cin >> var1;
cout << endl;
cout <<"Enter the operation to be perfomed : ";
cin >> operation;
cout << endl;
cout << "Enter the second nuber : ";
cin >> var2;
cout << endl;
bool right_input = false;
if (operation == '+') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 + var2);
right_input = true;
}
if (operation == '-') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '*') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 * var2);
right_input = true;
}
if (operation == '/' && var2 != 0) {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '/' && var2 == 0) {
cout << "Error. Division by zero.";
right_input = true;
}
if (!right_input) {
cout << var1 << " " << operation << " " << var2 << " = " << "Error;";
cout << "Invalid Operation!";
}
cout << endl;
system("pause");
return 0;
}
