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2 years ago

Can anyone plz help me ASAP? This is urgent, due by tmr! Plz help! Tysm

Mathematics

1 answer:

nadezda [96]2 years ago

4 0

Here's the equation,please do ask if you don't understand. Sorry for my terrible hand writing ^^; hope it helps!

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How do you solve this problem? What is a rewritten form of the radical(-8/726) It is supposed to be a squar root sign instead of

Mamont248 [21]

I think the answer is negative 8 square root 726

then the answer if I am right sorry if I am not would be negative 88 square root 6

again sorry if wrong

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2 years ago

If anyone needs help I Can help you

Nadya [2.5K]

I'll help. I love helping people

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3 years ago

Zeros:-3,0,4 degree:3

makkiz [27]

(X+3)(x)(x-4)

Hope that helps :)

5 0

3 years ago

Pleasee help me, I don’t get it

Aleks [24]

Answer:

x = 4 sqrt(5)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

8^2 + x^2 = 12^2

64+ x^2 =144

Subtract 64 from each side

x^2 = 144-64

x^2 =80

Take the square root of each side

sqrt(x^2) = sqrt(80)

x = sqrt(16*5)

x = 4 sqrt(5)

8 0

2 years ago

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp

olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = $\overline{x}$ = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data speeds i.e. x - $\overline{x}$

x - $\overline{x}$ = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between carrier's highest data speed and the mean of all 50 data speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

$\frac{59.98}{20.03}=2.99$

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

$z=\frac{x-\overline{x}}{s}$

Using the given values, we get:

$z=\frac{75.6-15.62}{20.03}=2.99$

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the carrier's highest data speed is significantly higher.

3 0

2 years ago