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3 years ago

In the triangle shown, find x.

Mathematics

1 answer:

jeka943 years ago

7 0

X=25 I hope my work makes sense

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What is the measure of AC 58 Degrees PLEASE HELP

Ann [662]

AC would be double of its angle, which happens to be 58.

58•2 = 116.

Therefore, your answer would be D: 116 degrees.

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Anyone know how to find the constant of proportionality???!!!

dmitriy555 [2]

Answer:

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Step-by-step explanation:

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3 years ago

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E. Solve the Inequality

olganol [36]

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$\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}$

Solve the Inequality.

$\blue{\textsf{\textbf{\underline{\underline{Answer:-}}}}$

x<-4

$\blue{\textsf{\textbf{\underline{\underline{How\:to\:Solve:-}}}}$

First, add 6x on both sides:

-2x+3+6x<-13

Add the x's:

4x+3<-13

Now, subtract 3 on both sides:

4x<-13-3

4x<-16

Divide by 4 on both sides:

x<-4

So the values of x that are less than -4 will make the given inequality true.

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7 0

2 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

3 0

3 years ago

3 3/4 divide 2 1/12<br><br><br> sssss

dybincka [34]

3 3/4 divide 2 1/12 = 1.8

8 0

3 years ago