well 1+1=2 and 2+2=4 and 4+4=8 and 8+8=16 then..............................................ummm.....................................uhhhhhhhh...........................wow this is hard.......................................................................I have no clue sorry thats all i know
Answer:
∠ ADC = 110°
Step-by-step explanation:
∠ CDE = 90° ( angle between perpendicular lines ) , then
∠ CDB + ∠ BDE = 90°
∠ CDB + 20° = 90° ( subtract 20° from both sides )
∠ CDB = 70°
∠ ADC and ∠ CDB are adjacent angles on a straight line and sum to 180° , so
∠ ADC + ∠ CDB = 180° , that is
∠ ADC + 70° = 180° ( subtract 70° from both sides )
∠ ADC = 110°
<span>(4*10^2)(2*10^5)
= 8 x 10^7
hope it helps</span>
I don't really like these algebra problems which pretend to be geometry.
The bisector makes two equal angles, so
x/2 + 17 = x - 33
50 = (1/2) x
x = 100
That means ABC = 100/2 + 17 = 67 degrees
CBD = 100 - 33 = 67 degrees, equal so that checks
We're asked for ABC which is 67 + 67 = 134 degrees
Answer: 134°
Answer:
k=20.
Explanation: First we find where f(x) has its local extrema: f'(x)=3x2−10x+3. The critical points are roots of the equation: 3x2−10x+3=0.
