Answer:
There might be more to this problem that not included?
Based on the question written, J and Q would be anything that is mathematically supported.
I could a virtually endless combination, that's why I think we may be missing part of the question.
Here are some solutions:
J=11, Q = 6 11-5=6
J=12, Q= 7 12-5=7
J= 7, Q = 2 7-5=2
J = 162, Q = 157 162-5=157
The vertex of the quadratic function is: A) (0,2)
Answer:
50%
Step-by-step explanation:
TRUST
Y - 3 = -1/4(x - 4)
y - 3 = -1/4x + 1
y = -1/4x + 1 + 3
y = -1/4x + 4
ok....the y int is (0,4)....the slope is -1/4...
x int can be found by subbing in 0 for y and solving for x
y = -1/4x + 4
0 = -1/4x + 4
1/4x = 4
x = 4 * 4
x = 16....so ur x int is (16,0)
so first plot ur points (0,4)....and since ur slope is -1/4, go down 1 space and to the right 4 spaces, then down 1, and to the right 4....keep doing this and u will cross the x axis at (16,0)
Step-by-step explanation:
/qiq-iorx-dxr
Meet
anyone come
