Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or
ft
=
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
=
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k(
)
k = 18
Work done (W) to stretch the spring by
ft will be
W = ![\int\limits^\frac{11}{12} _0 {kx} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B11%7D%7B12%7D%20_0%20%7Bkx%7D%20%5C%2C%20dx)
= ![\int\limits^\frac{11}{12} _0 {(18x)} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B11%7D%7B12%7D%20_0%20%7B%2818x%29%7D%20%5C%2C%20dx)
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9(
)²
= 7.56 lb-ft
Answer: 20+2x=y
Step-by-step explanation:
C is the correct answer because I guessed
<span>Solve for x
-x=-5
multiply both sides by (-1)
</span>-x (-1) =-5 (-1)
simplify
x = 5
answer is 5 (positive 5)
Answer:
1/12
Step-by-step explanation:
Given the following :
Actual height of pyramid = 24 ft
Dimension of scaled model :
Height = 2ft ; width = 1ft
a scale factor is a number used to reproduce a reduced dimension of a model by multiplying the actual dimeznsion or size of the model or object.
Since the height is of the scaled model is less than the actual height of the pyramid ; then it could be said that the scale factor is a fraction, because reduction has occurred.
(Height of scaled model / height of actual pyramid)
(2ft / 24ft) = 1/12