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emmasim [6.3K]
3 years ago
6

What is 6 minus 3 5/6?

Mathematics
2 answers:
madreJ [45]3 years ago
7 0

the answer is 3 5/6 because there you’re dealing with a whole number and a mixed number, so all you have to do is 6-3, which is 3 and add the 5/6.

Leviafan [203]3 years ago
4 0

Answer:

<u><em>2.16 or  2  1/6</em></u>

Step-by-step explanation:

first we convert the mixed numbers to improper fractions, then find the lcd (least common denominator) and then we combine:

13/6

<em>decimal form: 2.16</em>

<em>mixed number form : 2  1/6</em>

<em />

<em>×║hope this helps you║×</em>

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kiruha [24]

both are 2

check

2²+3(2)-10=0

4+6-10=0

10-10=0

0=0

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2 years ago
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2 years ago
A = 1/2f(s + z) for s<br><br> Solve the following formula for the specified variable
Marat540 [252]

Step-by-step explanation:

\huge{\mathtt{\red{\underbrace{\overbrace{\pink{\boxed{\boxed{\blue{answer}}}}}}}}}

It is a little unclear when you state the problem what exactly is going on with that fraction. This is a common issue when you try to type up equations. On the right side, you have a fraction bar and then a bunch of stuff after it. We need to clear up what is supposed to be in the numerator and what is supposed to stay in the denominator. This is important not just for typing up questions on the internet to get help but in using your calculator as well. If what the equation means is that both "f" and "q+z" are in the denominator, but then on your calculator you type something 1 / 2 * f * ( q + z ), most calculators (e.g. TI 83/84 and almost any basic or scientific model) will interpret that as meaning only the 2 is on the bottom and the rest is on top.

If you meant the f and the q+z are on top, then Steve's answer is good.

If you meant the f and the q+z are supposed to be on the bottom, then we have a little bit different process.

First, write down the operations that are happening to q, and in what order they happen from inside out, that is, according to the regular PEMDAS rule:

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2. 2f is multiplied

3. The result is divided into 1 (as opposed to being divided by 1).

So, to solve for q, we "invert" the order of operations and do the inverse operation of our 3 steps, and also in reverse order.

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q+z = 1/[2Cf]. Notice how I put brackets around the entire denominator so it's clear!

3. Finally to invert Step 1 we subtract z:

q = 1/[2Cf] - z

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3 years ago
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I believe this would be the solution.
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