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strojnjashka [21]
3 years ago
13

A bag contains 10 marbles: 4are green, 2are red, and 4 are blue. Carmen chooses a marble at random, and without putting it back,

chooses another one at random. What is the probability that both marbles she chooses are blue?
Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0

|\Omega|=10\cdot9=90\\|A|=4\cdot3=12\\\\P(A)=\dfrac{12}{90}=\dfrac{2}{15}

kupik [55]3 years ago
4 0

Answer:

2/15

Step-by-step explanation:

There is a 4/10 probability that she chooses blue the first time, but the second time it is a 3/9 chance because she didn't put the marble back so there are 9 marbles in total, 3 blue ones.

4/10 x 3/9 = 2/5 x 1/3 = 2/15

I hope this helps :)

Edit: Messed up the multiplication, whoops!

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vlabodo [156]

Answer:

6cm^{2} (assuming the units is in centimetres)

Step-by-step explanation:

Hi, hope this helps!

Method 1:

Calculate this shape as a trapezium. This is a trapezium because it has one pair of parallel sides. The way to calculate the area of a trapezium is this:

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In this case, 4 and 2 are parallel, so we add them together (4 + 2 = 6) then we divide by two (6 ÷ 2 = 3). Then we multiply our answer by the perpendicular length between the two parallel sides (assuming the side on the left is at a right-angle, 3 x 2 = 6).

Method 2:

Calculate this shape as a rectangle + a triangle. If you split the shape so the pointy bit on the right becomes a triangle and the left becomes a square, you can calculate the area without knowing the formula for calculating a trapezium (see above ^).

- Area of the square / rectangle = length x width = 2 x 2 = 4

- Area of the triangle = 1/2 x length x width = 2 x 2 x 1/2 = 4 x 1/2 = 4 ÷ 2 = 2

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I hope this helped and I wasn't waffling on :)

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