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4 years ago

The order in which you perform operations in a numerical expression does not matter

Mathematics

1 answer:

Rama09 [41]4 years ago

5 0

Answer:

False

Step-by-step explanation:

The given statement: 'the order in which you perform operations in a numerical expression does not matter' is absolutely false.

The order or sequence in which a mathematical expression is solved does matter a lot. Performing mathematical operations in a different manner will result in different results.

The rule for performing mathematical operation states that a numerical expression should be solved in the following manner:

1. Brackets

2. Of

3. Division

4. Multiplication

5. Addition

6. Subtraction

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About 6% of the population has a particular genetic mutation. 100 people are randomly selected. Find the standard deviation for

Marina86 [1]

Answer:

The standard deviation for the number of people with the genetic mutation in such groups of 100= $2.375$

Step-by-step explanation:-

We are given that

Total number of selected people, n=100

p=6%=0.06

We have to find the standard deviation for the number of people with the genetic mutation in such groups of 100.

Let X denote the number of people with the genetic mutation in such groups of 100.

$\implies X\sim Bin(n=100,p=0.06)$

We know that

Standard deviation

= $\sqrt{np(1-p)}$

Using the formula

Standard deviation

= $\sqrt{100\times 0.06(1-0.06)}$

= $\sqrt{6(0.94)}$

= $2.375$

Hence, the standard deviation for the number of people with the genetic mutation in such groups of 100= $2.375$

8 0

3 years ago

Jeremy buys 1,045 ceramic tiles. He can take 25 tiles to his truck at a time in his shopping cart. What is the minimum number of

kirill [66]

Answer:

Step-by-step explanation:

its 41.8, but you cant take 41.8 trips, so you have to round it

5 0

3 years ago

Read 2 more answers

What method would be best to use 53=4(x-3)^2-11

Veronika [31]

Answer:

x = 7 , -1

Step-by-step explanation:

SOLUTION :-

$4(x-3)^2-11 = 53$

Add 11 to both the sides.

$=> 4(x-3)^2-11+11=53+11$

$=> 4(x-3)^2 = 64$

Divide both the sides by 4.

$=> \frac{4(x-3)^2}{4} = \frac{64}{4}$

$=> (x-3)^2 = 16$

Root square both the sides.

$=> \sqrt{(x-3)^2} = \sqrt{16}$

$=> x-3 = +4 \; or -4$

Here , x will have two values -

1) $x-3 = 4$

$=> x = 4 + 3 = 7$

2) $x - 3 = -4$

$=> x = -4 + 3 = -1$

VERIFICATION :-

When x = 7 ,

$4(x-3)^2 - 11 = 4(7 - 3)^2 - 11$

$= 4 \times 4^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

When x = -1 ,

$4(x-3)^2 - 11 = 4(-1 - 3)^2 - 11$

$= 4 \times (-4)^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

7 0

3 years ago

(x^4)^2 please answer I need an A

scoray [572]

Answer:

x^8

Step-by-step explanation:

5 0

3 years ago

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2x - 5 + ¾ (4x - 8) =19

rosijanka [135]

It would most likely equal to 6. Hope this helped.

Step-by-step explanation:

8 0

3 years ago