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frosja888 [35]
3 years ago
15

2 over 5 as a percent

Mathematics
2 answers:
Dvinal [7]3 years ago
6 0
2/5 = 20/50 = 40/100 = 40%
Papessa [141]3 years ago
3 0

\frac{2}{5} = 40%

Work is attached in the image provided.

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What is the value of x in the equation 4x + 8y=40 when y=0.8
Fed [463]
8*.8=6.4 
4x+6.4=40
40-6.4=33.6
33.6/4=x
8.4=x

Hope this helps :)
8 0
3 years ago
Read 2 more answers
Maria mixes \frac{1}{4} cup white sugar and \frac{2}{3} cup brown sugar to make a topping for some muffins. She uses \frac{1}{12
Hoochie [10]

Answer: 11 muffins

Step-by-step explanation:

Since Maria mixes 1/4 cup white sugar with 2/3 cup brown sugar, this will give us a mixture of:

= 1/4 + 2/3

= 3/12 + 8/12

= 11/12

Ww are then told that she uses 1/12 cup of the mixture to top each muffin. Therefore, the number of muffins that she can top will be:

= 11/12 ÷ 1/12

= 11/12 × 12/1

= 12

She can top 11 muffins.

3 0
3 years ago
I need help with my math
mrs_skeptik [129]

Answer:

A=28

B=18

C=18

D=28

E=28

F=18

G=10

H=5

Step-by-step explanation:

3 0
2 years ago
A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r
Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, n(S)=6

Now, probability of rolling a 3 is given as:

P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0
3 years ago
How much do u need to subtract from 41/6 to make 6
dem82 [27]
41/6-5/6 = 36/6
36/6= 6

So 5/6 would need to be subtracted to develop a fraction that divides to 6
4 0
3 years ago
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