Answer:
1 - sin² θ = 1 - ( 1 - cos² θ) = cos² θ
tan x csc x = (sin x / cos x) * 1 / sin x = cos x
Step-by-step explanation:
1 - sin² θ = 1 - ( 1 - cos² θ) = cos² θ
tan x csc x = (sin x / cos x) * 1 / sin x = cos x
Answer:
(0,0)
Step-by-step explanation:
(x,y)= ( (x1 +x2)/2 , (y1+ y2)/2 )
= ( -7+7/2 , 7-7/2)
= (0/2 , 0/2)
= (0,0)
Therefore, the midpoint is at interval (0,0)
Answer:
??? and 0
Step-by-step explanation:
Ok I don't know about the first one but all I know is that it has 0 reflectional symmetries. Apologies for that but I wish you luck on your work and hopefully this somewhat helps a bit. ;-D