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tresset_1 [31]
3 years ago
14

A bus gets off the freeway, stops at a rest stop for passengers to get lunch, and then gets back on the freeway.

Mathematics
2 answers:
vladimir1956 [14]3 years ago
8 0

<u>Answer-</u>

<em>The </em><em>first graph</em><em> correctly describes the situation.</em>

<u>Solution-</u>

First scenario-

As the bus gets off the freeway, that means the driver pushed the brake. That is why the speed decreases constantly to zero. So the slope is negative here.

Second scenario-

As the bus stops at the rest stop for passengers to get lunch, the vehicle is still. As the bus is in still position, so its speed is zero as long it is still at the rest stop. So the slope is zero here.

Third scenario-

As the bus now starts moving towards freeway, its speed increases constantly. So the slope is positive in this case.

lozanna [386]3 years ago
5 0
I believe the first graph in the shape of the \_/ is the correct graph because when he gets off the freeway his speed slows then he stops and is no longer moving for a period of time. Then he gets back on and his speed is going up. 
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Monday through Thursday, the movie theater sold 439 tickets. Over the weekend,
velikii [3]

Answer:

560

Step-by-step explanation:

You subtract 439 from 999 and you get the left over tickets that were sold over the weekend

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3 years ago
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mars1129 [50]
Hi there,
This is the original inequality equation:
\frac{x}{x+1} \ \textless \  \frac{x}{x-1}
So, we first need to find the critical points of equality, and we can do that by switching the less than sign to an equal sign.
\frac{x}{x+1} = \frac{x}{x-1}
Now, we multiply both sides by x + 1:
x= \frac{x^{2} +x}{x-1}
Then, we multiply both sides by x - 1:
x^{2} -x= x^{2} +x
Next, we subtract x² from both sides:
-x=x
After that, we solve for x. We do this by adding -x to both sides and dividing by 2. Doing so gives us x = 0, which is our first critical point. We need to find a few more critical points by testing x = -1 and x = 1. Here is how we do that:
<span>x = <span>−1 </span></span>(Makes left denominator equal to 0)<span>x = 1   </span>(Makes right denominator equal to 0)Check intervals in between critical points. (Test values in the intervals to see if they work.)<span>x <<span>−1    </span></span>(Doesn't work in original inequality)<span><span><span>−1 </span>< x </span><0  </span>(Works in original inequality)<span><span>0 < x </span>< 1 </span>(Doesn't work in original inequality)<span>x > 1  </span><span>(Works in original inequality)
Therefore, the answer to your query is -1 < x < 0 or x > 1. Hope this helps and have a phenomenal day!</span>
4 0
3 years ago
The flight of a cannonball toward a hill is described by the parabola y=2+0.12x- 0.0004x^2
Stells [14]

The computation shows that the placw on the hill where the cannonball land is 3.75m.

<h3>How to illustrate the information?</h3>

To find where on the hill the cannonball lands

So 0.15x = 2 + 0.12x - 0.002x²

Taking the LHS expression to the right and rearranging we have:

-0.002x² + 0.12x -.0.15x + 2 = 0.

So we have -0.002x²- 0.03x + 2 = 0  

I'll multiply through by -1 so we have

0.002x² + 0.03x -2 = 0.

This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.

The second solution y = 0.15 * 25 = 3.75

Learn more about computations on:

brainly.com/question/4658834

#SPJ4

Complete question:

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

6 0
2 years ago
Did I do my math homework right?
anastassius [24]
Yes you did it correctly but change problem 5’s denominator on the right to a 6
7 0
3 years ago
The equation y = 0.25x describes a proportional relationship between x and y. What is the constant of proportionality?
hoa [83]

Answer:

k = 0.25

Step-by-step explanation:

The standard equation of a proportional relationship is

y = kx ← k is the constant of proportion

y = 0.25x ← is in this form

with k = 0.25

8 0
3 years ago
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