Answer:
3. A=B=70°; C=D=110°
4. A=90°; C=48°
Step-by-step explanation:
Same-side angles of a trapezoid add to 180°.
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3. (2x) +(x+15) = 180
3x + 15 = 180 . . . . simplify
x +5 = 60 . . . . . . . divide by 3
x = 55
A=B=(x+15)° = (55+15)° = 70°
C=D=2x° = 2·55° = 110°
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4. You are given the values of one of the angles on each side, so the other can be found by subtraction:
A=180°-D = 90°
C = 180° -132° = 48°
Good morning,
Answer:
<h2>5+(-4) > -4 + (-7)</h2>
Step-by-step explanation:
5+(-4) = 5 - 4 = 1
-4 + (-7) = -(4+7) = -11
since 1 > -11 then 5+(-4) > -4 + (-7)
:)
Here is the set up:
Let m = mass of the block
m = (30•40•50)/(2.8)
Use your calculator to calculate the left side for m.
The tank can hold 31.8 gallons of water.
Answer:
C.(3|-4)
Step-by-step explanation:
Given the vector:
![\left[\begin{array}{ccc}4\\3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
The transformation Matrix is:
![\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C-1%260%5Cend%7Barray%7D%5Cright%5D)
The image of the vector after applying the transformation will be:
![\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C-1%260%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C3%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2A4%2B1%2A3%5C%5C-1%2A4%2B0%2A3%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C-4%5Cend%7Barray%7D%5Cright%5D)
The correct option is C
