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DaniilM [7]
3 years ago
12

Which financial statement is prepared first?

Mathematics
2 answers:
MrRissso [65]3 years ago
8 0
Income statement is first
IRISSAK [1]3 years ago
7 0
Income statement ............... ...
You might be interested in
A rectangular field has an area 28800 sq.meter.its length is twice as long as its width.what is the length of its sides?
AVprozaik [17]
Let 
x---------> the length side of rectangle
y---------> the width side of rectangle

we know that
x=2y-----> equation 1
area=x*y-------> 28800=x*y------> equation 2
substitute 1 in 2

28800=[2y]*y-----> 28800=2y²-------> y²=14400------> y=120 m
x=2*y----> x=2*120------> x=240 m

the answer is
the length side of rectangle is 240 m
 the width side of rectangle is 120 m


5 0
3 years ago
Please help. 20 points! and brainliest!
rjkz [21]

Answer:

7=285

8=4.8

9=8

Step-by-step explanation:

mark brainlyest

4 0
3 years ago
Which pair of numbers has GCF of 5
finlep [7]
The only pairs for the greatest common factors of 5 are 1, 5
8 0
3 years ago
(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul
Aloiza [94]

Answer

(a) F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

Step-by-step explanation:

(a) f(t) = 20.5 + 10t + t^2 + δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 f(s)e^{-st} \, dt

where a = ∞

=>  F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt

where d(t) = δ(t)

=> F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt

Integrating, we have:

=> F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3}  )\left \{ {{a} \atop {0}} \right.

Inputting the boundary conditions t = a = ∞, t = 0:

F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) f(t) = e^{-t} + 4e^{-4t} + te^{-3t}

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt

F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt

F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt

Integrating, we have:

F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.

Inputting the boundary condition, t = a = ∞, t = 0:

F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

3 0
3 years ago
PLEASE HELP!!!!!!!!!!
AnnZ [28]

Given:

The graph of an exponential function.

To find:

The function in the form of f(x)=ab^x.

Solution:

The general form of an exponential function is

f(x)=ab^x                ...(i)

From the given graph it is clear that the function passes through the points (0,4) and (1,7). It means these points will satisfy the function.

For x=0 and f(x)=4,

4=ab^0

4=a(1)

4=a

For x=1 and f(x)=7,

7=ab^1

Putting a=4, we get

7=4(b)

\dfrac{7}{4}=b

Substitute a=4 and b=\dfrac{7}{4} in (i).

f(x)=4\left(\dfrac{7}{4}\right)^x

Therefore, the required exponential function is f(x)=4\left(\dfrac{7}{4}\right)^x.

8 0
3 years ago
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