Question

What is the factorization of 121b4-49

Answer 1

Since 121 is a perfect square, 12x12, and 49 is a perfect square, 7x7, and b^4 is a perfect square, b^2xb^2, you have what's called the difference of perfect squares. These factor into the sum and difference of the square roots. So (11b^2+7)(11b^2-7)

Answer 2

Answer:

The factorization of the expression is $121b^4-49=(11b-7)(11b+7)$

Step-by-step explanation:

Given : Expression $121b^4-49$

To find : What is the factorization of given expression?

Solution :

Expression $121b^4-49$

Using algebraic identity,

$x^2-y^2=(x+y)(x-y)$

Making the term in square form,

$121b^4=(11b)^2$

$49=7^2$

So,  $121b^4-49=(11b)^2-7^2$

Applying property,

$121b^4-49=(11b-7)(11b+7)$

Therefore, The factorization of the expression is $121b^4-49=(11b-7)(11b+7)$