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Tasya [4]
3 years ago
10

Four students are asked to find the mass of a mineral using a calibrated balance. The results were as follows: 16.009 g, 15.780

g, 16.110 g, and 15.990 g. The known mass of the mineral is 16.100g. Which student's result was the most accurate?
Mathematics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

There are two results that could be consider the most accurate:

1. 16.110g

Step-by-step explanation:

Since the actual mass is 16.100g. The result above is within ±0.01. That is, the most accurate results should be within the range of ±0.01.

Hence;

The result that can be consider most accurate is:

=> 16.100±0.01 = [16.110]

All other results are at distance above ±0.01 from the actual values 16.100g

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Find the solutions to 2x⁴-24x²+40=0 and the x-intercepts of the graph of y=2x⁴-24x²+40.
jekas [21]

Answer:

The solutions and the x-intercepts of the polynomial 2x^4-24x^2+40 are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Step-by-step explanation:

Given a function <em>f</em> a solution or a root of <em>f</em> is a value x_{0} at which f(x_0)=0.

An x-intercept is a point on the graph where y is zero.

To find the solutions of the polynomial and the x-intercepts 2x^4-24x^2+40 you need to:

First, we need to factor the polynomial expression

Factor the common term

{\left(2 x^{4} - 24 x^{2} + 40\right)} = {\left(2 \left(x^{4} - 12 x^{2} + 20\right)\right)}

We can treat x^{4} - 12 x^{2} + 20 as a quadratic function with respect to x^2

Let u=x^2. We can rewrite x^{4} - 12 x^{2} + 20 in terms of u as follows:

u^2-12u+20

We need to solve the quadratic equation

u^2-12u+20=0

for this we can use the Quadratic Equation Formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-12,\:c=20:\quad u_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}

u_1=\frac{-\left(-12\right)+\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_1=10

u_2=\frac{-\left(-12\right)-\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_2=2

the solutions to the quadratic equation are:

u=10,\:u=2

Therefore, u^2-12u+20=(u-10)(u-2)

Recall that u=x^2 so

2 x^{4} - 24 x^{2} + 40=2 \left(x^{2} - 10\right) \left(x^{2} - 2\right)=0

Using the Zero factor Theorem: If ab = 0, then either a = 0 or b = 0, or both a and b are 0.

x^2-10=0 roots are x_1=\sqrt{10}; x_2=-\sqrt{10}

x^{2} - 2=0 roots are x_1=\sqrt{2}; x_2=-\sqrt{2}

The solutions and the x-intercepts are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Because all roots are real roots the x-intercepts and the solutions are equal.

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3 years ago
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liubo4ka [24]
Try this explanation+solution:
1. According to the given graph it is possible to define A - amplitude and B - frequency of this function, then to substitute them to its equation.
2. A=5 (max. and min. values for vertical); B=2 (two periods in the length 2π).
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3 years ago
Find the measure of AC.
alexira [117]

Answer:

AC = 23 so it be D

Step-by-step explanation:

plug AC = DF ---> 21x-19 = 3x+17

sub. 3x by both sides --> 18x-19 = 17

add 19 to both sides --> 18x = 36

divide both sides by 18, x = 2

plug x back into 21x-19 to find AC

21(2) - 19

42 - 19 = 23

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Answer: 21599373.37618

Step-by-step explanation:

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Answer:

x = 5

Step-by-step explanation:

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x² + 12² = 13²

x² + 144 = 169 ( subtract 144 from both sides )

x² = 25 ( take the square root of both sides )

x = \sqrt{25} = 5

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4 years ago
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