Answer: P(B|G) = 3/5 = 0.6
the probability that the guest is the friend of bride, P(bride | groom) is 0.6
Complete Question:
The usher at a wedding asked each of the 80 guests whether they werea friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Given that the randomly chosen guest is the friend of groom, what is the probability that the guest is the friend of bride, P (bride | groom)
Step-by-step explanation:
The conditional probability P(B|G), which is the probability that a guest selected at random who is a friend of the groom is a friend of the bride can be written as;
P(B|G) = P(B∩G)/P(G)
P(G) the probability that a guest selected at random is a friend of the groom.
P(G) = number of groom's friends/total number of guests sample
P(G) = 50/80
P(B∩G) = the probability that a guest selected at random is a friend is a friend of both the bride and the groom.
P(B∩G) = number of guests that are friends of both/total number of sample guest
P(B∩G) = 30/80
Therefore,
P(B|G) = (30/80)/(50/80) = 30/50
P(B|G) = 3/5 = 0.6
Answer:
Step-by-step explanation:
answer
15.9454=15.9
Answer: 5489
Step-by-step explanation:
Given the following :
Growth rate (r) = 19% per hour
Sample culture in population = 2300
Size of sample after 5 hours =?
Using the exponential relation:
P = Po * r^t
P = population after 5 hours
Po = Initial sample population
t = time
P = 2300 * (1 +19%)^t
P = 2300 ×(1 + 0.19) ^5
P = 2300 * 1.19^5
P = 2300 * 2.3863536599
P = 5488.61341777
P = 5489 (nearest integer)
Answer:
(301)^2-(300)^2
it is in the form of
a^2-b^2=(a+b)(a-b)
so,
(301+300)(301-300)
(601)(1)=601
Answer:
4 sqrt(3) =x
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp / hyp
sin 60 = x / 8
8 sin 60 = x
8 ( sqrt(3)/2) = x
4 sqrt(3) =x
