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AfilCa [17]
3 years ago
6

PLEASE HELP ME WITH THIS STUPID QUESTION!!!! WHAT DO I HAVE TO PUT IN THE BOX!! 30pts. Will mark brainliest!!!

Mathematics
1 answer:
dsp733 years ago
4 0

2

-10 and 10 are 10 units from 0 on the number line

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Determine the zeros of the expression -16t^2-8t+24.
Lina20 [59]
-16t^2-8t+24=-8(2t^2+t-3)=-8(2t^2+3t-2t-3)\\\\=-8[t(2t+3)-1(2t+3)]=-8(2t+3)(t-1)\\\\\text{the zeros}\\\\2t+3=0\to t=-1.5\\t-1=0\to t=1\\\\Answer:\ \boxed{-1.5\ and\ 1}
6 0
2 years ago
Angle mIJK=180, angle mIJU = 3x-7, and angle mUJK=17x + 7 find angle mIJU
Andrej [43]

Answer:

The measure of angle IJU is 20 degrees.

Step-by-step explanation:

In order to find that, we need to add the two angles together and set equal to 180 degrees. Then we can solve for x.

(3x - 7) + (17x + 7) = 180 ----> Combine like terms

20x = 180 -----> Divide by 20

x = 9

Now that we have this, we can stick the value into the equation and solve for IJU.

IJU = 3x - 7

IJU = 3(9) - 7

IJU = 27 - 7

IJU = 20

3 0
2 years ago
Somebody help and explain!!!
Maslowich

Answer: The midpoint of segment PQ is the number 2.5

note: 2.5 as a fraction is 5/2; as a mixed number 2.5 converts to 2&1/2

============================================================

Explanation:

Apply the midpoint formula to get the midpoint of -8 and 6

We simply add up the values and divide by 2 and we get (-8+6)/2 = -2/2 = -1

So point Q is at -1 on the number line, which is exactly halfway from R to P

Focus on just points P and Q now. Apply the midpoint formula again

Q = -1

P = 6

(Q+P)/2 = (-1+6)/2 = 5/2 = 2.5

So the midpoint of segment PQ is 2.5

The decimal 2.5 can be written as the mixed number 2&1/2, showing that this new point is exactly halfway between 2 and 3.

4 0
3 years ago
The revenue R you receive for selling pizza slices depends on the price p that you charge per slice and is modeled by R =-16p
sp2606 [1]

Answer:

p \geq 0

Step-by-step explanation:

Given

R(p) = -16p^2 + 80p + 5

Required

Determine the domain of the function

To do this, we need to solve for the vertex, p of the function

p= \frac{-b}{2a}

Given the the general form of a quadratic function is:

y = ax^2 + bx + c

By comparison, we have:

a = -16    b =80    c = 5

So:

p= \frac{-b}{2a}

p = \frac{-80}{-16 * 5}

p = \frac{-80}{-80}

p = 1

Substitute 1 for p in R(p) = -16p^2 + 80p + 5

R(1) = -16(1)^2 + 80(1) + 5

R(1) = -16 + 80 + 5

R(1) = 69

This implies that

(p, R) = (1,69)

The interpretation of this is that;

<em>For every value of p, there's a corresponding value of R.</em>

<em>However, because p indicates price and it's impossible to have a negative price, we can say that the minimum value of p is 0;</em>

Hence, the domain is

p \geq 0

8 0
3 years ago
Help pls!!
vladimir2022 [97]

Answer:

1/4

Step-by-step explanation:

5 + 7 + 4 = 16

4/16 = 1/4

pls give me brainliest :)

4 0
3 years ago
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