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Nata [24]
3 years ago
10

Darla bought 0.9 kilogram of red grapes and 0.35 kilogram of green grapes.

Mathematics
1 answer:
madam [21]3 years ago
3 0

keep trying good luck to you

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Natalie buys a basketball for $25.57 and an air pump for $15.61. How much change will she receive if she pays for both items wit
DaniilM [7]

Answer:

8.82

Step-by-step explanation:

Add the basketball and airpump together and subtract from 50

3 0
3 years ago
Read 2 more answers
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
Section 5.2 Problem 6:<br><br>Find the general solution<br><img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2
mihalych1998 [28]

Answer:

y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Step-by-step explanation:

<u>Given Second-Order Homogenous Differential Equation</u>

y''+6y'+10y=0

<u>Use Auxiliary Equation</u>

<u />m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i

<u>General Solution</u>

<u />y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Note that the DE has two distinct complex solutions p\pm qi where A and B are arbitrary constants.

4 0
2 years ago
What is lcm and gcf of 6a and 8b
Feliz [49]
Lcm is 24 and the  gcf is 2
8 0
3 years ago
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Which fraction is in reduced form?
kompoz [17]

Answer:

  C  5/13

Step-by-step explanation:

A fraction is written in reduced form if there are no common factors in the numerator and denominator. Since you know your multiplication tables, you can easily identify the common factors:

  A 20 = 5·4, so 4 is a common factor 4/(4·5) = 1/5

  B 6 = 2·3, 9 = 3·3, so 3 is a common factor (2·3)/(3·3) = 2/3

  C 13 is not a multiple of the prime number 5, so there are no common factors. 5/13 is a reduced fraction

  D 14 = 2·7, 21 = 3·7, so 7 is a common factor (2·7)/(3·7) = 2/3

8 0
3 years ago
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