Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m
g(x) = x^2 + 1(3x - 5)
<em><u>Replace all x's with 4.</u></em>
g(4) = 4^2 + 1(3 * 4 - 5)
g(4) = 16 + 1(12 - 5)
g(4) = 17(7)
g(4) = 119 (This is your answer.)
Answer:
Hey there!
The first equation has no solutions, as it is parallel lines.
The second equation has infinitely many solutions, as it is basically the same line, and the two lines intersect at infinite points.
The third equation is just one solution.
Let me know if this helps :)
Answer:
or 
Step-by-step explanation:
The volume of a cylinder is calculated by the following formula

Where r is the radius of the cylinder and h is the height
In this case we know that the radius r of the base is:

and

So the Volume is:


