come on now, the amplitude is always the coefficient of the trigonometric function.
Answer:
f(1) = 11
Step-by-step explanation:
f(x) = 3x + 8
Let x=1
f(1) = 3(1) +8
= 3+8
= 11
The quadrants is tan⁻¹x restricted is A. Quadrants I and IV
To answer the question, we need to know what tan⁻¹x is.
<h3>What is tan⁻¹x?</h3>
tan⁻¹x is the inverse trigonometric function of tanx, which is the value of the angle for tanx.
<h3>Quadrant in which tan⁻¹x is restricted</h3>
To find the quadrants in which tan⁻¹x is restricted, we know that tanx lies in the range
-∞ ≤ tanx ≤ +∞ for -90° ≤ x ≤ 90°.
- Since the inverse function of tanx is x.
- tan⁻¹x lies between -90° and 90°. That is -90° ≤ tan⁻¹x ≤ 90°.
- Since 90° lies in first quadrant and -90° lies in the fourth quadrant
tan⁻¹x lies between quadrant I and IV
So, the quadrants is tan⁻¹x restricted is A. Quadrants I and IV
Learn more about tan⁻¹x here:
brainly.com/question/20334292
#SPJ1
Two litres.
1000ml=1l
2000ml=2l
