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Scilla [17]
3 years ago
7

Ktoś mi to rozwiarze pls

Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0

a)

2a+(3a-7)=2a+3a-7=5a-7

b)

(2x-3)+x=2x-3+x=3x-3

c)

7-(5x+4)=7-5x-4=3-5x

d)

3x-(y-2x)=3x-y+2x=5x-y

e)

-(3a+6)-4=-3a-6-4=-3a-10

f)

-(x-2y)-3x=-x+2y-3x=2y-4x

g)

(2p-1)+(3+5p)=2p-1+3+5p=7p+2

h)

(4-2x)-(7x-2)=4-2x-7x+2=6-9x

i)

-(2x-1)+(3x+1)=-2x+1+3x+1=x+2

j)

(2m+4n)+(m-0,5n)=2m+4n+m-0,5n=3m+3,5n

k)

(4a-7b)-(2a+3b)=4a-7b-2a-3b=2a-10b

l)

-(2p-r)-(2r-p)=-2p+r-2r+p=-p-r

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Answer:

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Since the line we are supposed to find is parallel to y = -5/4x - 5 that means they are going to have the same slope. The line we are looking for is of the following type: y = -5/4 x + b

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