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3 years ago

3x+7=13 (x=-2;x=2;x=5)

Mathematics

2 answers:

AnnZ [28]3 years ago

5 0

X=2 because 3 times 2 is 6 and then you add 6 and 7 together and get 13.

IgorLugansk [536]3 years ago

3 0

Answer: x=2

Step-by-step explanation:

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Which of the following choices is the x intercept of the equation 2y-x=-6

Rashid [163]

Answer:

$x = 6$

Step-by-step explanation:

Given

$2y-x=-6$

Required

Determine the x intercept

To get the value of x intercept; we simply substitute 0 for y;

i.e. y = 0

$2y-x=-6$ becomes

$2(0)-x=-6$

$0-x=-6$

$-x=-6$

Multiply both sides by -1

$-1 * -x=-6 * -1$

$x=-6 * -1$

$x = 6$

<em>Hence, the x intercept is 6</em>

6 0

3 years ago

What is the following sale price for a phone charger with an original price of $1.99 after applying a discount of 20%

Zarrin [17]

Answer:

$1.59

Step-by-step explanation:

7 0

3 years ago

2/5 x 3 as a fraction

Svet_ta [14]

Answer:

1 1/5

Step-by-step explanation:

2/5 x 3 as a Fraction = 1 1/5

Improper Fraction = 6/5

Mixed Number = 1 1/5

8 0

3 years ago

Read 2 more answers

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 16, b = 17 (5

Blizzard [7]

Answer:

B = 61.75°

Step-by-step explanation:

The formula for the Law of Sines is given as:

a/ sin A = b/ sin B

In the question, we are given the following values

A = 56°, a = 16, b = 17

We are to solve for B

Hence,

16/ sin 56° = 17/sin B

Cross Multiply

sin B × 16 = sin 56° × 17

sin B = sin 56° × 17/16

sin B = 0.88

B = arc sin(0.88)

B = 61.74536°

Approximately B = 61.75°

7 0

3 years ago