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4 years ago

Unjumble the letters to find a word from .iecjut

English

2 answers:

ikadub [295]4 years ago

8 0

there are two words like juice ,cutie

UNO [17]4 years ago

5 0

Juice is one the options while the other is cute

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My favorite flavors ice cream or strawberry coffee and chocolate identify the error in this sentence

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my favorite flavors of ice cream are strawberry,coffee,and chocolate .

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3 years ago

The Elephant and the Crocodile

Brrunno [24]

Answer:

Everyone is special in his or her own way.

Explanation:

One person's strength is another's weakness. We all have areas of expertise/specialty/usefulness and this differentiates us from the next person

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2 years ago

PLEASE ANSWER

Nana76 [90]

Answer:

its A it flows better then and now

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3 years ago

In the case below, the original source material is given along with a sample of student work. Determine the type of plagiarism b

irinina [24]

Answer: Paraphrasing plagiarism

Explanation: Although the student acknowledge the original author in the first sentence by putting it in quote and citing the author, the student just paraphrased the next sentence without putting it in quote and without citation. That is definitely plagiarism. Paraphrasing plagiarism is the act of changing the wordings of the original idea or work of the author while it still has thesame meaning and not give citation of the source.

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3 years ago

I will make you brainlist if you help me the 2 question by explain them i swear i will make you brainlist

Xelga [282]

★ Formula Applied :

$\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}$

$\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}$

$\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}$

$\bullet\ \; \sf \ln (ab)=\ln a+\ln$

★ Explanation :

$\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}$

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

$\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}$

$\to \sf \red{-ln|sin2x|+c}$

$\to \sf - \ln |2sinx.cosx|+c$

$\to \sf - \ln |sinx.cosx|+(\ln 2+c)$

$\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar$

★ Alternate Method :

$\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}$

$\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx$

$\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}$

$\to \sf ln\left| \dfrac{secx}{sinx}\right|+c$

$\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}$ ]

$\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar$

4 0

3 years ago