Answer:
No DB is not a perpendicular bisector of AC
Step-by-step explanation:
This is because as AC is a straight line it's angle degree is 180 which when bisected by DB becomes,
180 ÷ 2 = 90
On both the angles i.e <BDC = <NDA = 90°
To make it a perpendicular bisector but
<BDC is not equal to <NDA is not equal to 90°.
Hence, DB is not a perpendicular bisector of line AC.
Answer:
Step-by-step explanation:
we know that distance d from the focus to P should be the same to the distance from P to the directrix
(x-h)^2=4p(y-k)
we need to find the y coordinate,
x is the same from focus, 3
y=(3, (4+2)/2)=(3,3)
we find p now by subtracting the y from the focus from the y that we just found
p=4-3=1
again (x-h)^2=4p(y-k), p=1
(x-3)^2=4(1)(y-3)
(x-3)^2=4(y-3), (x-3)^2=4y-12
simplify
4y=(x-3)^2+12
y=((x-3)^2)/4 + 3
You would multiply 16*3 to get an estimate.
16*3= 48
The bike would be about 48 units.
I'm assuming you mean a 16:1 scale.
16:1= 16/1 which =16
Hope this helps!
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