I’m still confused on how to do combinations and permutations?
1 answer:
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Answer:
about 2949 feet
Step-by-step explanation:
The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...
Tan = Opposite/Adjacent
__
<h3>setup</h3>Filling in the known values, we have ...
tan(6°) = (310 ft)/(distance to coyote)
<h3>solution</h3>Multiplying by (distance to coyote)/tan(6°) gives ...
distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft
distance to coyote ≈ 2949.453 ft
The coyote is about 2949 feet from the base of the cliff.
Answer:
1). System of equations- D + Q = 90 and D + 2.5Q = 175.50
2). There are 33 dimes and 57 quarters in the bank.
Step-by-step explanation:
Dylan has a bank that sorts coins as they are dropped in it.
A panel shows the total number of coins inside as well as the total value of these coins.
Let the number of dimes in the bank = D
and the number of quarters in the bank = Q
If the panel shows total number of coins = 90
Then the equation will be
D + Q = 90 -------(1)
And the panel displays the amount of the coins = $17.55
Then equation will be
0.10D + 0.25Q = 17.55 [1 Dime = $0.10 and 1 quarter = $0.25]
D + 2.5Q = 175.50 ------------(2)
Now we subtract equation (1) form equation (2)
D + 2.5Q - (D + Q) = 175.50 - 90
D + 2.5Q - D - Q = 85.5
1.5Q = 85.5
Q =
= 57
By putting Q = 57 in the equation (1)
D + 57 = 90
D = 90 - 57 = 33
Therefore, there are 33 dimes and 57 quarters in the bank.