tam olmasada yaklaşık 6.5 günde bitter
Answer:
correct option is △XYZ ~ △X'Y'Z'.
Step-by-step explanation:
since ΔXYZ is dilated by some scale factor so, the resulting triangle can not be congruent to the ΔXYZ. so option 2 is wrong.
as we have explained that the two triangles are not congruent then it's sides and angles also can't be congruent so, option 3 is also incorrect.
As we don't know by what factor the triangle XYZ is dilated so we can't say anything about correctness of option 4 and 5.
ΔXYZ was reflected over a vertical line and then dilated so the resulting ΔX'Y'Z' is similar to ΔXYZ.
i.e., △XYZ ~ △X'Y'Z'.
Answer:
5.4
Explanation:
I multiplied 18.6 by the answer choices that should give me 100.44. But the shortcut to this is to divide the area by it’s height.
Answer:
x = 15
Step-by-step explanation:
9x - 5 = 7x + 25 ......(vertical angle and corresponding angle )
9x - 7x = 25 + 5
2x = 30
x = 30 / 2
x = 15
Answer:
the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;
![\frac{\pi }{2} [e^2 - 1 ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Be%5E2%20-%201%20%5D)
or 10.036
Step-by-step explanation:
Given the data in the question;
y = 
, y = 0, x = 1, x = 2.
Now, using the integration capabilities of a graphing utility
y = 
, y = 0
Volume = 
Volume = 
Volume = 
Volume = 
Volume = ![\frac{\pi }{e^2} [\frac{e^{2x}}{2}]^2_1](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7Be%5E2%7D%20%20%5B%5Cfrac%7Be%5E%7B2x%7D%7D%7B2%7D%5D%5E2_1)
Volume = ![\frac{\pi }{2e^2} [e^4 - e^2 ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2e%5E2%7D%20%20%5Be%5E4%20-%20e%5E2%20%5D)
Volume = or 10.036
Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;
or 10.036
