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Anestetic [448]
3 years ago
6

The Royal Fruit Company produces two types of fruit drinks. The first type is

Mathematics
1 answer:
Dimas [21]3 years ago
4 0
Now, the percentage figures of say, 70%, 95% and so on, we'll use the decimal format of the, thus 70% is just 70/100 or 0.7 and 95% is just 95/100 or 0.95 and so on

so  \bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentration\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{70\% pure}&x&0.7&0.7x\\
\textit{95\% pure}&y&0.95&0.95y\\
-----&-----&-------&-------\\
mixture&160&0.85&(160)(0.85)
\end{array}

whatever "x" and "y" amounts are, we know, they must add up to 160 pints
thus  x + y = 160

now, whatever the concentrated amount of solute in the mixture, we know they must add up to 160*0.85 or 136

thus   0.7x + 0.95y = 136

thus    \bf \begin{cases}
x+y=160\implies \boxed{y}=160-x\\
0.7x+0.95y=136\\
----------\\
0.7x+0.95\left( \boxed{160-x} \right)=136
\end{cases}

solve for "x", to see how much of the 70% pure juice will be needed

what about "y"?  well, y = 160 - x
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Please solve this GIVING BRAINLIEST and pls show proof!
storchak [24]

Answer:

b

Step-by-step explanation:

to prove if NP is tangent to MN

we could prove if NPM is a right triangle

By pythagorean theorem

a^2+b^2=c^2

where a=MN=33

b=NP=180

c=MP=MQ+QP=152+33=185

so

33^2+180^2=185^2

but

1089+32400 is not equal to 34225

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7 0
3 years ago
Deon earns $91 washing 7 dogs. At this rate, how many dogs did Deon wash to earn $117?​
mamaluj [8]
$91/ 7 = $13 per dog
$117/$13 = 9 dogs
He washed 9 dogs
4 0
3 years ago
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
Quick anyone know this algebra 2 problem?
anastassius [24]

I believe it's the 3rd one

3 0
3 years ago
What is the length of BC in the right triangle below?
gayaneshka [121]

Hey there! :)

Answer:

C. BC = 39 units.

Step-by-step explanation:

Use the Pythagorean theorem to solve for BC. Let BC = c, AB = a, and AC = b.

c² = a² + b²

c² = 15² + 36²

Square and simplify:

c² = 225 + 1296

c² = 1521

c = √1521

c = 39 units.

Therefore:

BC = 39 units.

5 0
3 years ago
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