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arlik [135]
3 years ago
14

Can you help me on number 4

Mathematics
2 answers:
Licemer1 [7]3 years ago
8 0
The answer is b
and do you mine helping with 6 grade math expression and equations follow Ms and you will get it quicker
GenaCL600 [577]3 years ago
8 0
Hello :3

the answer is b) -Irys
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What is the midpoint of the segment below?
In-s [12.5K]

Answer:

Your answer is A.(7,3)

7 0
2 years ago
Jane bough 1.5 pounds of chicken, then went back to the store and bought 1 13/16 More pounds, how many total pounds did she buy
Studentka2010 [4]

Answer:

Step-by-step explanation:

1.5 + 1 13/16

O.5 = 1/2

(1+1)+(1/2 + 13/16)

2 + (8/16 + 13/16) = 2 21/16

4 0
2 years ago
PLEASE HELP!!
Montano1993 [528]
Your method is right so u already know how to do it
7 0
3 years ago
Tonya has a box that measures 12 cm by 7 cm by 19cm. what is the volume of the box. Please help
kaheart [24]

Answer: 1,596 cubic cm. To find the volume, you need to multiply all the three sides given.


Step-by-step explanation:

12cm * 7 cm* 19cm = 1596 cm^3


4 0
3 years ago
A flow meter is attached in a hydraulic line that measures 18 gal/min. The line has an inside diameter of 1.0 in. What is the fl
snow_tiger [21]

The flow velocity measured as in/min at the meter is 5924.13 in/min

<h3 /><h3>Volumetric flow rate</h3>

We know that the volume flow rate Q = Av where

  • A = cross-sectional area of pipe and
  • v = flow velocity

Now, Q = 18 gal/min

Converting this to in³/min, we have

Q = 18 gal/min = 18 × 1 gal/min = 18 × 231 in³/min = 4158 in³/min

A = πd²/4 where d = diameter of pipe = 1.0 in.

<h3 /><h3>Flow velocity, v</h3>

Since Q = Av, making v subject of the formula, we have

v = Q/A

v = 4Q/πd²

Substituting the values of the variables into the equation, we have

v = 4Q/πd²

v = 4 × 4158 in³/min ÷ π × (1.0 in)²

v = 16632 in/min ÷ π

v = 5924.13 in/min

So, the flow velocity measured as in/min at the meter is 5924.13 in/min

Learn more about flow velocity here:

brainly.com/question/15648466

5 0
2 years ago
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