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Dahasolnce [82]
3 years ago
8

As each layer of the OSI model adds its encapsulation header and/or footer, the ______ gets larger until it reaches the physical

layer at which time it leaves the device for delivery.
Computers and Technology
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

Message

Explanation:

  • The Application layer creates a message. The Application layer passes the message to the Presentation layer.
  • The Presentation layer encapsulates the message by adding information to it. Information is usually added only at the beginning of the message (called a header); however, some layers also add material at the end of the message (called a footer)
  • The process of passing the message down and adding layer-specific information continues until the message reaches the Physical layer.
  • At the Physical layer, the message is converted into electrical impulses that represent bits and is transmitted over the physical connection.  
  • The receiving computer captures the bits from the physical connection and re-creates the message in the Physical layer.  
  • The Physical layer converts the message from bits into a Data Link frame and sends the message up to the Data Link layer.
  • The Data Link layer strips its information and sends the message up to the Network layer.
  • This process of deencapsulation is performed until the message reaches the Application layer.
  • When the message reaches the Application layer, the data in the message is sent to the intended software recipient.
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MrMuchimi

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2 years ago
9.10: Reverse ArrayWrite a function that accepts an int array and the array ’s size as arguments . The function should create a
AleksandrR [38]

Answer:

#include <iostream>

using namespace std;

int * reverse(int a[],int n)//function to reverse the array.

{

   int i;

   for(i=0;i<n/2;i++)

   {

       int temp=a[i];

       a[i]=a[n-i-1];

       a[n-i-1]=temp;

   }

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}

int main() {

   int array[50],* arr,N;//declaring three variables.

   cin>>N;//taking input of size..

   if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..

   return 0;

   for(int i=0;i<N;i++)

   {

       cin>>array[i];//prompting array elements..

   }

   arr=reverse(array,N);//function call.

   for(int i=0;i<N;i++)

   cout<<arr[i]<<endl;//printing reversed array..

   cout<<endl;

return 0;

}

Output:-

5

4 5 6 7 8

8

7

6

5

4

Explanation:

I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.

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