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Alona [7]
4 years ago
13

If a borrower obtains an interest-only loan of $112,500 at an annual interest rate of 6%, what is the monthly interest payment (

rounded to the nearest $1)? $550 $563 $648 $675
Mathematics
1 answer:
olganol [36]4 years ago
6 0
$563

First you will need to find the annual interest amount. To do this you will need to find 6% of 112,500.

6% can be written in decimal form as .06, so we can multiply .06 to 112,500 to find the annual interest rate.

.06 • 112,500=6,750

6,750 is the annual interest amount.

The next part of the question asks the monthly interest rate. You know there are 12 months in a year so you can divide the annual interest amount by 12.

6,750÷12=562.5

$562.5 is the monthly interest payment and rounded to the nearest dollar would be

Choice 2: $563
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5 0
3 years ago
7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and<br> A = {6, 10, 14}, what is A'?
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The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

We are given the universal set as:

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We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

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Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

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brainly.com/question/2166579

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5 0
1 year ago
Which fraction is greater,​2⁄3​or​1⁄3 ? How do you now?
m_a_m_a [10]
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3 0
3 years ago
What initial investment must be made to accumulate $60000 in 17 years if the money is invested in a mutual fund that pays 12% an
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$7881.18

Step-by-step explanation:

   Let the initial Investment be P_{0}. The Interest is compounded on a monthly basis at 12% annual interest rate. After 17 years, the Investment amounts to $60,000.

   As the annual interest rate is 12%, the monthly interest rate is 1%.

Since this is a compound interest problem, the total amount can be modeled as follows: P(t)=P_{0}(1+\frac{i}{100})^{t}

Here i is the interest rate, i.e 1, and t is the number of time periods, i.e 17\textrm{ years x }12\frac{\textrm{months}}{\textrm{year}}= 204\textrm{ months}

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P_{0}=7881.18

∴ Initial Investment = $7881.18

4 0
3 years ago
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klasskru [66]

Answer:

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