Notice that the given info consists of boundary lines for an area in the xy plane. We are interested ONLY in values of x and y that are 0 or greater (positive). Graph 5x + 3y

37 and 3x + 5y less than or equal to 35.
Find the points of intersection of all four straight lines (including the x- and y-axes). There will be 4 such points (incl. the origin).
Next, evaluate the objective function 2x + 14y at each of these 4 points. Which of the four results is the largest? the smallest? Label them as 'maximum' and 'minimum.'
Questions? Just comment on this discussion.
we are given


(A)
(f×g)(x)=f(x)*g(x)
now, we can plug it

we can simplify it


(B)
Domain:
Firstly, we will find domain of f(x) , g(x) and (fxg)(x)
and then we can find common domain
Domain of f(x):

we know that f(x) is undefined at x=0
so, domain will be
∪
Domain of g(x):

Since, it is polynomial
so, it is defined for all real values of x
now, we can find common domain
so, domain will be
∪
..............Answer
Range:
Firstly, we will find range of f(x) , g(x) and (fxg)(x)
and then we can find common range
Range of f(x):

we know that range is all possible values of y for which x is defined
since, horizontal asymptote will be at y=0
so, range is
∪
Range of g(x):

Since, it is quadratic equation
so, its range will be

now, we can find common range
so, range will be
∪
.............Answer
7: since they went down further you go further from zero: -28-40=-68 or D.
8: they lost 6 and then 8 so 6+8=14 but they lost them so -14 or A :)
Answer:
4.2
Step-by-step explanation:
Because RM and ML are the same, that makes KL and KR congruent. Hope his helps. :)
Answer:
See below
Step-by-step explanation:
<u>Given relationship:</u>
a) r = 3, d = 4
- t = d/r = 4/3 h = 1 h 20 min
b) d = 4 miles, rate = r
- t = 4/r, domain is r and must be greater than zero
c) d = 4 miles, time = t
- r = d/t = 4/t, domain is t and it must be greater than zero
d) t = 3 h, rate = r
- d = rt = 3r, domain is r and can be anything greater than zero