Sry idk wish I could know but good luck
Keywords:
<em>Division, quotient, polynomial, monomial
</em>
For this case we must solve a division between a polynomial and a monomial and indicate which is the quotient.
By definition, if we have a division of the form:
, the quotient is given by "c".
We have the following polynomial:
that must be divided between monomy
, then:
represents the quotient of the division:



Thus, the quotient of the division between the polynomial and the monomial is given by:

Answer:
The quotient is: 
Option: A
Answer:
<h2>The answer is 58 m</h2>
Step-by-step explanation:
Perimeter of a rectangle = 2l + 2w
where
l is the length
w is the width
From the question
length = 17 m
width = 12 m
Substitute the values into the above formula and solve for the perimeter
We have
Perimeter = 2(17) + 2(12)
= 34 + 24
We have the final answer as
<h3>58 m</h3>
Hope this helps you
Let's solve this problem step-by-step.
First of all, let's establish that supplementary angles are two angles which add up to 180°.
Therefore:
Equation No. 1 -
x + y = 180°
After reading the problem, we can convert it into an equation as displayed as the following:
Equation No. 2 -
3x - 8 + x = 180°
Now let's make (y) the subject in the first equation as it is only possible for (x) to be the subject in the second equation. The working out is displayed below:
Equation No. 1 -
x + y = 180°
y = 180 - x
Then, let's make (x) the subject in the second equation & solve as displayed below:
Equation No. 2 -
3x - 8 + x = 180°
4x = 180 + 8
x = 188 / 4
x = 47°
After that, substitute the value of (x) from the second equation into the first equation to obtain the value of the other angle as displayed below:
y = 180 - x
y = 180 - ( 47 )
y = 133°
We are now able to establish that the value of the two angles are as follows:
x = 47°
y = 133°
In order to determine the measure of the bigger angle, we will need to identify which of the angles is larger.
133 is greater than 47 as displayed below:
133 > 47
Therefore, the measure of the larger angle is 133°.