3 years ago

How is finding a peremiter of a triangle similar to finding the perimeter of a rectangle

Mathematics

1 answer:

skad [1K]3 years ago

4 0

They are both found by adding all the sides

You might be interested in

Please help!<br> 3x^2 + 1/2 x 7y (When y = 3)

Sholpan [36]

Factoring the equation:

3x^2 + 1/2 x 7(3)

3x^2 + 1/2 x 21

3 (x^2 + 1/2 x 21)

3 (x^2 + 7/2)

3 x 1/2 (2x^2 +7)

3/2 (2x^2 + 7)

7 0

2 years ago

Read 2 more answers

What are the next four terms in the following arithmetic sequence? (-7), (-2), 3, 8,... A. 18, 23, 28, 33 B. 13, 18, 23, 28 C. 8

Triss [41]

Ok..ur adding 5 each time to get the next term
so the next 4 terms are : 13, 18, 23, 28

5 0

2 years ago

Write each expression with fewer terms. Show or explain your reasoning.

liraira [26]

1. 103-22 = 81
2 10.2-3y+2x is already in simplest form

6 0

2 years ago

PLEASE HELP ME I HATE MATH.

dsp73

Answer:

BBBBBBBBBB

Step-by-step explanation:

1/4 mile per 22.5 seconds

7 0

2 years ago

3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu

djverab [1.8K]

Answer:

Probability distribution for x:

$P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\$

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

So, we have this probabilty distribution for x:

$P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\$

7 0

3 years ago