How is finding a peremiter of a triangle similar to finding the perimeter of a rectangle

Mathematics

1 answer:

skad [1K]3 years ago

4 0

They are both found by adding all the sides

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Alec paid the bill for dinner with his clients which totaled $140 before tax and tip. If an 8 percent sales tax was added to the

nlexa [21]

Answer:

176.2

Step-by-step explanation:

On a calendar you tyow 140 then add 8% then add 25.00

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3 years ago

In the figure, ABCD = EFGH. Identify all pairs of congruent corresponding

saveliy_v [14]

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3 years ago

◆ Quadratic Equations ◆<br>Please help !

Mila [183]

I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

$\sf ax^2+(1-a(b+c))x+abc-d)$

$\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))$

Simplify into standard form:

$\sf x^2+(1-1(5))x+6-4$

$\sf x^2+(1-5)x+2$

$\sf x^2-4x+2$

Use the quadratic formula to solve:

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

For functions in the form of $\sf ax^2+bx+c$ . So in this case:

a = 1
b = -4
c = 2

Plug them in:

$\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}$

Solve for 'x':

$\sf x=\dfrac{4\pm\sqrt{16-8}}{2}$

$\sf x=\dfrac{4\pm\sqrt{8}}{2}$

$\sf x\approx\dfrac{4\pm 2.83}{2}$

$\sf x\approx 0.59,3.41$

So the answer would be A.

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4 years ago

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Sloan [31]

I think it will be 1.000

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3 years ago

Read 2 more answers

Complete the equation of the line through (-9,-9) and (-6,0)

Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$