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3 years ago

3 loq, 6) - 2 log (5x) = 2

Mathematics

1 answer:

Scrat [10]3 years ago

4 0

Answer:

is this the answer im sorry i did not put steps i was in a hurry to go to the next class.

Step-by-step explanation:

y=10(log(5x)+1)/9lq(y,x)

l=0

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Which of the following describes how to translate the graph y=|x| to obtain the graph of y=|x-6|

Lera25 [3.4K]

You transformed the function as follows:

$f(x)\mapsto f(x-6)$

All trasformations of the fashion $f(x)\mapsto f(x+k)$ translate the function horizontally, k units right if k is positive, k units left if k is negative.

In your case, k=6, so you translated the original function y=|x| 6 units to the right.

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3 years ago

PLZ!!!!HELP!!!What is the absolute deviation for 15 in the data set?

Brut [27]

20 + 20 + 30 + 15 + 40 = 125
125/5= 25
25-15 = 10
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3 years ago

Read 2 more answers

That is, what is the 142nd odd number?

Kitty [74]

Answer and step-by-step explanation:

I believe it is 287. I am not entirely sure, but I believe that is the answer.

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2 years ago

A pelican is flying 120 feet above sea level. The pelican dives to catch a fish that is 35 feet below sea level. Which number re

sergiy2304 [10]

Answer:

155

Step-by-step explanation:

Remember that below sea level means negative. So 120-(-35)=155

I hope this helps! :)

8 0

3 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago