Answer:
Probability that an ear of corn selected at random will contain no borers is 0.4966.
Step-by-step explanation:
We are given that the distribution of the number of borers per ear approximated the Poisson distribution. The farmer counted 3,500 borers in the 5,000 ears.
Let X = <u><em>Number of borers per ear</em></u>
The probability distribution of the Poisson distribution is given by;
where,
= parameter of this distribution and in our question it is proportion of bores in the total ears =
= 0.7
SO, X ~ Poisson(
= 0.7)
Now, probability that an ear of corn selected at random will contain no borers is given by = P(X = 0)
P(X = 0) =
=
= <u>0.4966</u>
Hence, the required probability is 0.4966.