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Serhud [2]
4 years ago
10

Marcus drew a quadrilateral with only 1 pair of parallel sides. Which quadrilateral did Marcus draw?

Mathematics
2 answers:
Allisa [31]4 years ago
5 0
A trapezoid! 
Hope this helps! <3
Paul [167]4 years ago
4 0
That would be a trapezoid
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Find the slope of the line through the points (13,14) and (0,−1)
timofeeve [1]

Answer:

1.15 or \frac{15}{13}

Step-by-step explanation:

1. The slope can be found with this formula: \frac{y2-y1}{x2-x1}

2. Let's plug in the numbers: \frac{14--1}{13-0}

4. \frac{15}{13} ≈ 1.1538

6 0
2 years ago
What is the base 10 representation of the number 1046(8)
Hitman42 [59]

1046₈ = 1*8³ + 0*8² + 4*8¹ + 6*8⁰

1046₈ = 512 + 0 + 32 + 6

1046₈ = 550₁₀

8 0
3 years ago
Read 2 more answers
Draw a function of dy/dx for the graphical below (image). Please help!
fenix001 [56]

Step-by-step explanation:

Remember that

\frac{dy}{dx}

is the gradient or slope function.

So we need to analyze the slope of each graph over given time.l and how it changes.

For the 1st graph, we have a linear function.

Remember the special properties for all linear functions:

The slope at any two points on the line is the same.

So this means our slope here must be constant.

And since our slope is negative, our dy/dx, function must be a constant function that is negative. So

The answer for the first graph is draw a horizontal line underneath the x axis.

For the 2nd graph, we have a slope that is decreasing, reaches 0 at the minimum, then increases even more.

We can draw a linear function that is increasing forever for our dy/dx.

For the 3rd graph, we are increasing , till we hit 0, then decrease until we hit 0, then forever increases.

Our dy/dx will be a parabola that passes through the x axis twice at two different points, facing upwards.

The first , second, and third graph is the dy/dx graphs shown respectively.

All these are examples of possible graphs. If you need more clarification, let me know

4 0
2 years ago
Rate for 40 meters in 10 seconds?
Viefleur [7K]
The rate for 40 meters in 10 seconds is

40m/10sec (40 meters per 10 seconds)

You can turn it into a different unit of measurement by multiplication or division.

For example, if you want the rate in 1 second, you divide both units by 10 (because there are 10 seconds, and 10 ÷ 10 = 1).

40m/10sec then becomes

4m/1sec (4 meters per 1 second)

40 ÷ 10 = 4, and 10 ÷ 10 = 1

Or if you'd like it in minutes, you multiply both units by 6 (because there are 60 seconds in 1 minute, and 6 x 10 = 60).

40m/10sec becomes

240m/60sec = 240m/1min

40 x 6 = 240, 10 x 6 = 60 = 1 minute
7 0
3 years ago
Solving this word problem (linear systems) by elimination:
fenix001 [56]
Your equation would be:

(x+(x+120))/2=45265

If you set it equal to x, your answer is

45,205
8 0
3 years ago
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